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6.069 grams is the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid.
Explanation:
Balanced equation for the reaction:
2 Al + 6 HCl → 2 AlCl₃ + 3 H₂
data given:
mass of aluminum = 27 grams
atomic mass of one mole of aluminum = 26.89 grams/mole
formula to calculate number of moles:
number of moles = 
number of moles = 
= 1.004 moles of aluminum will react
from the balanced equation:
2 moles of Al reacted to form 3 moles of H2
1.004 moles of Al will produce x moles of H2
= 
x = 3.012 moles of H2 will be formed.
mass will be calculated as number of moles multiplied by atomic weight
mass of 3.012 moles of hydrogen ?(atomic weight of one mole H2 = 2.015 grams)
= 3.012 x 2.015
= 6.069 grams of H2 will be formed.
Answer:
10.875L
Explanation:
The problem here is a simple conversion. The conversion is from gal to liters Liter is a SI unit for recording volume as stated in the problem.
Given that:
1 gallon of water = 3.75L
2.90 gallon will be 2.9 x 3.75; 10.875L
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Answer:</h3>
1.926 g of NaOH
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Explanation:</h3>
Concept tested: Mole and Avogadro's number
- We need to know that , 1 mole of a compound contains number of molecules equivalent to the Avogadro's number.
- Th Avogadro's number is 6.022 × 10^23
Therefore;
- 1 mole of a compound = 6.022 × 10^23 molecules
In this case; Our compound is NaOH
Therefore;
1 mole of NaOH contains 6.022 × 10^23 molecules
But; Molar mass of NaOH is 40.0 g/mol
Therefore;
- 40.0 g of NaOH contains 6.022 × 10^23 molecules
With this we can calculate the mass of 2.90 × 10^22 molecules
- Mass of a compound = (number of molecules ÷ Avogadro's constant) × molar mass
Therefore;
Mass of NaOH =(2.90 × 10^22 molecules ÷ 6.022 × 10^23 molecules)40g
= 1.9263 g
= 1.926 g NaOH
Thus, the mass of NaOH is 1.926 g