Babylon
India submerged bodies
Greek
Microscope
Answer:
The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.
Answer:
8.8 cm
31.422 cm/s
Explanation:
m = Mass of block = 0.6 kg
k = Spring constant = 15 N/m
x = Compression of spring
v = Velocity of block
A = Amplitude
As the energy of the system is conserved we have
Amplitude of the oscillations is 8.8 cm
At x = 0.7 A
Again, as the energy of the system is conserved we have
The block's speed is 31.422 cm/s
Answer:
a. The one with the lesser mass.
Explanation:
Since , both are made of the same material , they will have same specific heat . On physical contact , heat will be exchanged between them with heat flowing from body at higher temperature to one at lower temperature . Amount of heat lost by one will be equal to amount of heat gained .
So temperature change will take place in both of them but they will not be same . Body of higher mass will undergo lesser change in temperature because of the following relation
Q = mcΔT
ΔT = Q / mc
ΔT ∝ 1 / m
change in temperature will be inversely proportional to mass of object if Q or heat exchanged is constant .
Answer:
0.087976 Nm
Explanation:
The magnetic torque (τ) on a current-carrying loop in a magnetic field is given by;
τ = NIAB sinθ --------- (i)
Where;
N = number of turns of the loop
I = current in the loop
A = area of each of the turns
B = magnetic field
θ = angle the loop makes with the magnetic field
<em>From the question;</em>
N = 200
I = 4.0A
B = 0.70T
θ = 30°
A = π d² / 4 [d = diameter of the coil = 2.0cm = 0.02m]
A = π x 0.02² / 4 = 0.0003142m² [taking π = 3.142]
<em>Substitute these values into equation (i) as follows;</em>
τ = 200 x 4.0 x 0.0003142 x 0.70 sin30°
τ = 200 x 4.0 x 0.0003142 x 0.70 x 0.5
τ = 200 x 4.0 x 0.0003142 x 0.70
τ = 0.087976 Nm
Therefore, the torque on the coil is 0.087976 Nm