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Leno4ka [110]
3 years ago
9

Reese put gravel, sand, and clay in a bottle. She added some water, shook the bottle, and left it for an hour. What did she see

after an hour?
Chemistry
2 answers:
meriva3 years ago
7 0

The heaviest material will settle at the bottom. The lightest material will settle at the top. Gravel is the heaviest.

so your answer will be Gravel settled at the bottom and clay settled at the top.

quester [9]3 years ago
3 0
<span>Gravel settled at the bottom and clay settled at the top.</span>
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67.029g to three significant figures
alexdok [17]
67.0 Should be th3 answer
5 0
3 years ago
Read 2 more answers
how many moles of silicon are in 245 g of silicon? a. 8.72 mol b. 28.0 mol c. 1.10 10-1 mol d. 6.90 103 mol
Salsk061 [2.6K]
Atomic mass silicon = 28.085 u

1 mol Si ---------------- 28.085 g  
?  ------------------------ 245 g

245 x 1 / 28.085 =><span> 8.72 mol</span>

<span>answer A</span>
7 0
3 years ago
A 6.175 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 13.30 g CO2 and 5.
Bingel [31]

Answer:

Empirical and molecular formulas are the same, C₅H₁₀O₂.

Explanation:

Hello!

In this case, when determining the empirical and molecular formulas of organic compounds via combustion analysis, we first need to compute the moles of carbon and hydrogen via the yielded mass of carbon dioxide and water:

n_C=13.30gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.30molC\\\\n_H=5.447gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.60molH

Next, we need to compute the mass of oxygen by subtracting the mass of carbon and hydrogen to the mass of the sample of the compound:

m_O =6.175g-0.3molC*12.01gC/molC-0.6molH*1.01gH/molH =1.966gO

And consequently the moles:

n_O=0.12molO

Now, we need to divide the moles of each atom by the fewest moles, it in this case, those of oxygen to obtain the subscripts in the empirical formula:

C=\frac{0.30}{0.12} =2.5\\\\H=\frac{0.60}{0.12} =5\\\\O=\frac{0.12}{0.12} =1

Thus, the empirical formula, taken the nearest whole number is:

C_5H_{10}O_2

Now, if we divide the molar mass of the molecular formula (102.1 g/mol) by that of the empirical formula (102.1 g/mol) we infer they are both the same.

Best regards!

6 0
2 years ago
A 0.80 L sample of gas has a temperature of 27°C and a pressure of 0.925 atm. How many moles of gas are present?
ololo11 [35]

Answer:

n= 0.03 moles

Explanation:

Using the ideal gas law:

PV=nRT

nRT=PV

n= PV/RT

 n: moles

 P: pressure in atm

 V= volume in L

 R= Avogadro's constant = 0.0821

 T= Temperature in K => ºC+273.15

n= (0.925 atm)(0.80 L) / (0.0821)(300.15 K)

n= 0.03 moles

6 0
3 years ago
Isobutylene is a hydrocarbon used in the manufacture of synthetic rubber. when 0.847 g of isobutylene was subjected to combustio
Firlakuza [10]
Find the mass of C in the 2.657 g CO2:
(2.657 g CO2) / (44.01 g/mol) = 0.06037 mol CO2
Since each mole of CO2 also has 1 mole of C, this is equivalent to 0.06037 mol C.

Find the mass of H in the 1.089 g H2O:
(1.089 g H2O) / (18.02 g/mol) = 0.06043 mol H2O
Since 1 mol H2O has 2 mol H, this is equivalent to (0.06043)*2 = 0.1209 mol H.

Taking the ratio of H to C: 0.1209 / 0.06037 = 2.002 ~ 2
Therefore, the empirical formula of isobutylene is CH2.
6 0
3 years ago
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