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Tcecarenko [31]
3 years ago
10

The set of chemical and physical properties of a ______ are different from those of its constituents.

Chemistry
1 answer:
Veronika [31]3 years ago
7 0

Answer:

compound

Explanation:

hope this helps

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Jason combines the two intermediate steps shown.
Snowcat [4.5K]

Answer:

Place two of them as reactants.

Explanation:

  • We have the two steps of reactions:

1) N₂(g ) + O₂(g) → 2NO(g).

2) 2NO(g )+ O₂(g) → 2NO₂(g).

  • Adding the two equation with cancelling the intermediate (NO), we get:

<em>N₂(g ) + 2O₂(g) → 2NO₂(g).</em>

<em></em>

NO is cancelled out because there is one in each equation in the products side in eq. 1 and in oriduct side in eq. 2.

<em>So, we place two of oxygen as reactants.</em>

7 0
3 years ago
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In the determination of iron in an ore, the ore (mostly Fe2O3) is first dissolved in HCl(aq). A slight excess of Sn2 is added to
katovenus [111]

Answer:

2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²

Explanation:

A redox reaction occurs between a compound that loses electrons and others that gain an electron. The first is being oxidized, and the other is being reduced.

In this situation, in the compound Fe₂O₃, the iron, has an oxidation number equal to +3, so it's Fe⁺³, and it will gain 1 electron to become Fe⁺². Because it was first dissolved in HCl, we must use the ion at the equation. The other compound Sn₂ will be oxidized to Sn⁺², so it will need to lose 2 electrons.

So, it will be necessary 2 Fe⁺³ for this reaction happen:

2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²

8 0
3 years ago
God Has Given wing To Birds ​
labwork [276]

Answer:

and birds can fly without wings es hora de vomer

3 0
2 years ago
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What is the ph of 0.450 m al(no3)3 [ka for al3+(aq) = 1.00x10-5]? express your answer to two decimal places?
White raven [17]

Answer : The pH of the solution is, 2.67

Explanation :

The equilibrium chemical reaction is:

                           Al^{3+}+H_2O\rightarrow Al(OH)^{2+}+H^+

Initial conc.       0.450                   0               0

At eqm.           (0.450-x)                 x               x

As we are given:

K_a=1.00\times 10^{-5}

The expression for equilibrium constant is:

K_a=\frac{(x)\times (x)}{(0.450-x)}

Now put all the given values in this expression, we get:

1.00\times 10^{-5}=\frac{(x)\times (x)}{(0.450-x)}

x=0.00212M

The concentration of H^+ = x = 0.00212 M

Now we have to calculate the pH of solution.

pH=-\log [H^+]

pH=-\log (0.00212)

pH=2.67

Therefore, the pH of the solution is, 2.67

8 0
3 years ago
What is the concentration of the acid in this titration 1.2 m 2.4 m 1.95 m 0.98 m 1.98 m
tresset_1 [31]

Answer:

1.95

Explanation:

Just did the test and it was correct!

5 0
3 years ago
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