The electric potential at a point in

Does a greater amount of force always result in a greater amount of work? Why or why not? Does moving an object a greater amount

Zina [86]

Thank you for posting your question here at brainly. I would say yes to the above question. Work done is the force applied multiplied by the distance travelled. Wd = F x d. So if d increases, Wd increases also. I hope the answer will help you.

5 0

2 years ago

The diameter of Circle A is _________. EF AG EG FG

Bond [772]

Answer:

The diameter is EF

Explanation:

Given

Circle A (See attachment)

Required

Determine the line that represents the diameter

First, it should be noted that the diameter of a circle is always a straight line.

From the attachment, the circle has the following straight lines:

E F
E A
A G
A F

It should also be noted that the diameter passes through the center of a circle and divides it into two congruent parts.

From the list of straight lines above, only line EF satisfy this property

Hence, the diameter of the circle is line EF.

6 0

3 years ago

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The distance between earth and mars is 51 G meters. What is the minimum RTT for a link between Earth and Mars if speed of light

beks73 [17]

Answer:

340 seconds = 5.667 minutes

Explanation:

As we know, S = v t or t = S / v (S = 51 x 10^9 m and v = 3 x 10^8 ms^-1)

So, t = 51 x 10^9 / 3 x 10^8 = 17 x 10^1 = 170 s

For a RTT estimation, the time span will be doubled of one way propagation for transmission and receive delay.

The over all round trip time will be = 170 x 2 = 340 seconds = 5.667 minutes

4 0

3 years ago

What did Niels Bohr discover?

saveliy_v [14]

Niels Bohr discovered of the nucleus and developed an atomic model

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

5 0

3 years ago

How much force would be needed to

Galina-37 [17]

There would be two forces acting on the box parallel to the floor, with a net force of

∑ F = p - f = m a

where p = magnitude of the push, f = mag. of friction, m = mass of the box, and a = acceleration. To find p, we first need f .

There are also only two forces acting on the box perpendicular to the floor, with net force

∑ F = n - w = 0

where n = mag. of normal force of the floor on the box and w = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.

w = m g, where g = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for n :

n = w = m g

n = (22 kg) (9.8 m/s²)

n = 215.6 N

The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, µ = 0.17, such that

f = µ n

f = 0.17 (215.6 N)

f = 36.652 N

Now solve for the required pushing force:

p - 36.652 N = (22 kg) (1.9 m/s²)

p ≈ 78 N

4 0

3 years ago

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