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kodGreya [7K]
3 years ago
5

The electric potential at a point in

Physics
1 answer:
Rudik [331]3 years ago
6 0

Answer:

11.3975

Explanation:

Accellus said so

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Does a greater amount of force always result in a greater amount of work? Why or why not? Does moving an object a greater amount
Zina [86]
Thank you for posting your question here at brainly. I would say yes to the above question. <span>Work done is the force applied multiplied by the distance travelled. </span><span>Wd = F x d. </span><span>So if d increases, Wd increases also. I hope the answer will help you. </span>
5 0
2 years ago
The diameter of Circle A is _________. EF AG EG FG
Bond [772]

Answer:

The diameter is EF

Explanation:

Given

Circle A (See attachment)

Required

Determine the line that represents the diameter

First, it should be noted that the diameter of a circle is always a straight line.

From the attachment, the circle has the following straight lines:

  • E F
  • E A
  • A G
  • A F

It should also be noted that the diameter passes through the center of a circle and divides it into two congruent parts.

From the list of straight lines above, only line EF satisfy this property

Hence, the diameter of the circle is line EF.

6 0
3 years ago
Read 2 more answers
The distance between earth and mars is 51 G meters. What is the minimum RTT for a link between Earth and Mars if speed of light
beks73 [17]

Answer:

340 seconds = 5.667 minutes

Explanation:

As we know, S = v t or t = S / v (S = 51 x 10^9 m and v = 3 x 10^8 ms^-1)

So, t = 51 x 10^9 / 3 x 10^8 = 17 x 10^1 = 170 s

For a RTT estimation, the time span will be doubled of one way propagation for transmission and receive delay.

The over all round trip time will be = 170 x 2 = 340 seconds = 5.667 minutes

4 0
3 years ago
What did Niels Bohr discover?
saveliy_v [14]

Niels Bohr discovered of the nucleus and developed an atomic model

PLEASE RATE AS THE BRAINLIEST ANSWER! THANK YOU! :)

5 0
3 years ago
How much force would be needed to
Galina-37 [17]

There would be two forces acting on the box parallel to the floor, with a net force of

∑ <em>F</em> = <em>p</em> - <em>f</em> = <em>m a</em>

where <em>p</em> = magnitude of the push, <em>f</em> = mag. of friction, <em>m</em> = mass of the box, and <em>a</em> = acceleration. To find <em>p</em>, we first need <em>f</em> .

There are also only two forces acting on the box perpendicular to the floor, with net force

∑ <em>F</em> = <em>n</em> - <em>w</em> = 0

where <em>n</em> = mag. of normal force of the floor on the box and <em>w</em> = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.

<em />

<em>w</em> = <em>m g</em>, where <em>g</em> = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for <em>n</em> :

<em>n</em> = <em>w</em> = <em>m g</em>

<em>n</em> = (22 kg) (9.8 m/s²)

<em>n</em> = 215.6 N

The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, <em>µ</em> = 0.17, such that

<em>f</em> = <em>µ</em> <em>n</em>

<em>f</em> = 0.17 (215.6 N)

<em>f</em> = 36.652 N

Now solve for the required pushing force:

<em>p</em> - 36.652 N = (22 kg) (1.9 m/s²)

<em>p</em> ≈ 78 N

4 0
3 years ago
Read 2 more answers
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