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inessss [21]
2 years ago
7

Using the periodic table, determine which element these characteristics MOST LIKELY describe.

Physics
2 answers:
cupoosta [38]2 years ago
6 0

Answer:

Oxygen, fluorine and iodine are diatomic elements. Flourine is more reactive than the other two because it is the closest away to filling its outer layer of electrons and becoming stable like a noble gas.

Explanation:

hope this helps

densk [106]2 years ago
4 0

where the characteristics  ?!

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A boat with a horizontal tow rope pulls a water skier. She skis off to the side, so the rope makes an angle of 12.0 ∘ with the f
Sladkaya [172]

Answer:

62.601kJ

Explanation:

We have a force with a horizontal component given by the angle of 15°. So wue can take this component to calculate the total work done, that is,

W_T = Fd(cos\theta)

Our values are,

d=320m

Angle = 12\°

Force=200N,

Substituting in Work equation,

W_T = 200(320)(cos12)

W_T = 62601.4J

W_T = 62.601kJ

4 0
2 years ago
A spherical balloon is inflated with gas at the rate of 500 cubic centimeters per minute. How fast is the radius of the balloon
Nookie1986 [14]

Answer:

<h2>0.245cm/min</h2>

Explanation:

The volume of the spherical balloon is expressed as V = 4/3πr³ where r is the radius of the spherical balloon. If the spherical balloon is inflated with gas at the rate of 500 cubic centimetres per minute then dV/dt = 500cm³.

Using chain rule to express dV/dt;

dV/dt = dV/dr*dr/dt

dr/dt is the rate at which the radius of the gallon is increasing.

From the formula, dV/dr = 3(4/3πr^3-1))

dV/dr = 4πr²

dV/dt = 4πr² *dr/dt

500 =  4πr² *dr/dt

If radius r = 40;

500 = 4π(40)² *dr/dt

500 = 6400π*dr/dt

dr/dt = 500/6400π

dr/dt = 5/64π

dr/dt  = 0.245cm/min

Hence, the radius of the balloon is increasing at the rate of 0.245cm/min

8 0
3 years ago
A 200 kg weather rocket is loaded with 100 kg of fuel and fired straight up. It accelerates upward at 30 m/s2 for 35 s , then ru
Gre4nikov [31]

Answer:

a) h_m=74625\ m

b) t=265.55\ s

Explanation:

Given:

  • mass of rocket, m_r=200\ kg
  • mass of fuel, m_f=100\ kg
  • acceleration of the rocket consuming fuel, a=30\ m.s^{-2}
  • time after which the fuel exhaust, t_f=35\ s

<u>During the phase of fuel exhaustion:</u>

<u>velocity attained by the rocket just as the fuel ends:</u>

v_f=u+a.t_f

where:

u= initial velocity of the rocket = 0

v_f=0+30\times 35

v_f=1050\ m.s^{-1} this will be the initial velocity for the phase of ascending of the rocket's height under the influence of gravity.

<u>height at which the fuel finishes:</u>

v_f^2=u^2+2a.h_f

1050^2=0^2+2\times 30\times h_f

h_f=18375\ m

<u>During the phase of ascend in height of rocket after the fuel is over:</u>

<u>Time taken to reach the top height after the fuel is over:</u>

v=v_f+g.t'

at top v = (final velocity during this course of motion )= 0 m.s^{-1}

0=1050-9.8\times t'

t'=107.1429\ s

<u>Height ascended by the rocket after the fuel is over:</u>

v^2=v_f^2+2g.h'

at the top height the velocity is zero

0^2=1050^2-2\times 9.8\times h' (-ve sign denotes that the direction of motion is opposite to that of acceleration)

h'=56250\ m

<u>Therefore the maximum altitude attained by the rocket:</u>

h_m=h_f+h'

h_m=18375+56250

h_m=74625\ m

b)

time taken by the rocket to fall back to the earth:

h_m=v.t_m+\frac{1}{2} g.t_m^2

where:

v= initial velocity of the rocket during the course of free fall from the top height.

74625=0+4.9\times t_m^2

t_m=123.41\ s

Now the total time for which the rocket is in the air:

t=t_f+t'+t_m

t=35+107.1429+123.41

t=265.55\ s

4 0
3 years ago
A ball thrown straight up takes 1.89s to reach a height of 41.6m.
yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

8 0
3 years ago
How much work is done by gravity when a pine cone (of mass 50g) falls from the top of a tree, 9 m high?
Ksenya-84 [330]

4.5 Joules. I think it'd be 4.41, but when you round it, it's 4.5.

5 0
3 years ago
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