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inessss [21]
3 years ago
7

Using the periodic table, determine which element these characteristics MOST LIKELY describe.

Physics
2 answers:
cupoosta [38]3 years ago
6 0

Answer:

Oxygen, fluorine and iodine are diatomic elements. Flourine is more reactive than the other two because it is the closest away to filling its outer layer of electrons and becoming stable like a noble gas.

Explanation:

hope this helps

densk [106]3 years ago
4 0

where the characteristics  ?!

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What happens to the distance between interference fringes if the separation between two slits is increased?
kolezko [41]

Answer:

It will decrease

Explanation:

The double-slit interference equation, which gives us the position y of a maximum on the screen (measured relative to the central position), is

y=\frac{n\lambda D}{d}

where

n is the order of the maximum

D is the distance between the slits and the screen

\lambda is the wavelength of the light

d is the separation between the two slits

From the formula, we see that y is inversely proportional to d: this means that if the separation between the slits is increased, the distance of each maximum from the central position (y) decreases, therefore the distance between the interference fringes will decrease.

3 0
3 years ago
An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the
Marysya12 [62]
We can find the force by using the following formula;
N = ma +  mg
Fa = ma = 76 x 1.2 = 91.2
Fg = mg = 76 x 9.8 = 744.8
N = 91.2 + 744.8 = 836
So, the force is 836 N.
8 0
4 years ago
What happens when light is allowed to pass through a suspension
Nutka1998 [239]

Answer:

When light is passed through a true solution, the dissolved are too small to deflect light. suspensions may scatter light, but if the number of suspended particles is sufficiently large, the suspension may simply be opaque, and the light scattering would not occur.

3 0
4 years ago
Read 2 more answers
Electromagnetic waves are classified into forms such as radio waves, microwaves, and infrared waves, based on the amount of ener
Anna [14]

Answer: D) wavelength

Explanation:

The energy E of an electromagnetc wave is given by the following formula:  

E=h.f (1)

Where:  

h is the Planck constant  

f is the frequency  

Now, the frequency has an inverse relation with the wavelength \lambda:  

f=\frac{c}{\lambda} (2)  

Where c is the speed of light in vacuum

Substituting (2) in (1) we have:

E=\frac{hc}{\lambda} (3)

This means the amount of energy an electromagnetic wave carries depends on its wavelength (or its frequency), because the speed of light and h are constant.

6 0
3 years ago
Read 2 more answers
A. How many calories are needed to raise the temperature of 1 gram of water by 1 °C?
sweet-ann [11.9K]

A) 1 cal

B) 80 cal

C) 540 cal

Explanation:

A)

The amount of heat energy needed to raise the temperature of a certain mass of a substance is given by

Q=mC\Delta T

where

m is the mass of the substance

C is the specific heat capacity

\Delta T is the change in temperature

In this problem:

m = 1 g is the mass of water

C=1 cal/g^{\circ}C is  the specific heat capacity of water

\Delta T=1^{\circ}C is the change in temperature

So, the heat needed is

Q=(1)(1)(1)=1 cal

B)

For a solid substance at its melting point, the amount of heat needed to melt completely the substance is given by

Q=m\lambda_f

where

m is the mass of the substance

\lambda_f is the specific latent heat of fusion of the substance

In this problem:

- The ice is already at melting point, 0 °C

- Mass of the ice: m=1g

- Specific latent heat of fusion of ice: \lambda_f=80 cal/g

So, the heat needed is

Q=(1)(80)=80 cal

C)

For a liquid substance at its boiling point, the amount of heat needed to boil completely the substance is given by

Q=m\lambda_v

where

m is the mass of the substance

\lambda_v is the specific latent heat of vaporization of the substance

In this problem:

- The water is already at boiling point, 100 °C

- Mass of the water: m=1g

- Specific latent heat of vaporization of water: \lambda_v=540 cal/g

So, the heat needed is

Q=(1)(540)=540 cal

5 0
4 years ago
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