Answer:
C) ![\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4%7D)
Step-by-step explanation:
![k\times5=5+k](https://tex.z-dn.net/?f=k%5Ctimes5%3D5%2Bk)
![5k-k=5](https://tex.z-dn.net/?f=5k-k%3D5)
![4k=5](https://tex.z-dn.net/?f=4k%3D5)
![k=\frac{5}{4}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B5%7D%7B4%7D)
Answer: That is a great question.
Step-by-step explanation:
Answer:
The inequality x3 − 14x2 + 48x − 1,680 ≤ 0 can be used to find pool’s length.
⇒The water level in the pool cannot exceed 14 feet.
Step-by-step explanation:
The question is on inequalities
Given;
Length= x ft
depth= x-6 ft
Width= x-8 ft
volume ≤ 1680 ft³
Forming the inequality to find length x of the pool
Volume= base area × depth
base area × depth ≤ volume
x(x-8) × (x-6) = 1680
(x²-8x )(x-6) = 1680
x(x²-8x) -6 (x²-8x)=1680
x³-8x²-6x²+48x=1680
x³-14x²+48x=1680
x³-14x²+48x-1680 ≤ 0
⇒The water level in the pool cannot exceed 14 feet...why?
taking the value of x at maximum to be 17 according to the graph, then maximum depth will be;
d=x-6 = 17-6=11 ft
⇒11 ft is less than 14ft
The LCM is Least Common Multiple, it is the product of the highest order of occurring primes in the numbers prime factorization...
Using the quadratic formula, you can solve this quite easily.,,,,
a b c
x² - 12x + 59 = 0 a(1)...b(-12).....c(59)
(-b +/- √b² - 4ac) / (2a) (substitute the values for a, b, and c)
(-(-12) +/- √ (-12)² - 4 (1) (59)) / 2(1)
(12 +/- √-92) / 2 ( √-92 can be written as √-1√4√23)
(12 +/- √-1√4√23) / 2 (√-1 = i and √4 = 2)
6 +/- 23i