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3 years ago

Convert 23 calories into kcal

Chemistry

2 answers:

AVprozaik [17]3 years ago

6 0

0.023, to do it, just simply divide the energy value by 1000.

ValentinkaMS [17]3 years ago

3 0

0.023 is 23 calories converted to kcal

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A natural atom possesses the atomic number of 13 and a atomic mass of 27. Three electrons are lost. From what region of the atom

Anarel [89]

Answer:

The electrons are lost from the valence shell (outermost electron shell) of the atom.

Explanation:

This is able to be inferred not only because valence electrons being lost first is a trend but also because the atom in question has actually 3 valence electrons (13-2-8 = 3).

7 0

2 years ago

A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur

lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g$

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$q=m\times c\times \Delta T$

q = heat absorbed by water

$m$ = mass of water = 40.0 g

$T_{final}$ = final temperature of water = 20.0°C

$T_{initial$ = initial temperature of water = 17.0°C

$c$ = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

$q=40.0\times 4.186\times (20.0-17.0)]$

$q=502J$

Hence, the joules of heat were re-leased by the lead is 502

5 0

3 years ago

The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti

maksim [4K]

The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>

Half-life (t½) = 4 days
Time (t) = 4 weeks = 4 × 7 = 28 days
Number of half-lives (n) =?

n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>

Original amount (N₀) = 100 g
Number of half-lives (n) = 7
Amount remaining (N)=?

N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>

Original amount (N₀) = 100 g
Amount remaining (N)= 0.78125 g

Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

7 0

2 years ago

QUESTION 3 A series of electrolytic deposition experiments is conducted. In each case, 10.0 Faradays is passed through the indiv

Neporo4naja [7]

The greatest molar amount of metal product is obtained from silver (1) nitrate.

Let us determine the mass of metal obtained in each case.

For La^3+;

La^3+ + 3e ----> La

1 mole of La is deposited by 3F

x moles of La is deposited by 10 F

x = 1 × 10/3

x = 3.33 moles

For Zn^2+;

1 mole Zn^2+ is deposited by 2F

x moles of Zn^2+ is deposited by 10 F

x = 5 F

For Ag^+

1 mole of Ag^+ is deposited by 1 F

x moles of Ag^+ is deposited by 10 F

x = 10 moles

For Ba^2+;

1 mole of Ba^2+ is deposited by 2 F

x moles of Ba^2+ is deposited by 10 F

x = 5 moles

Learn more: brainly.com/question/967776

6 0

2 years ago

Chem !! 15 pts + brainliest

evablogger [386]

Answer:

V = 80.65L

Explanation:

Volume = ?

Number of moles n = 5 mol

Temperature (T) = 393.15K

Pressure = 1520mmHg

Ideal gas constant (R) = 62.363mmHg.L/mol.K

According to ideal gas law,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles of the gas

R = ideal gas constant (note this can varies depending on the unit of your variables)

T = temperature of the ideal gas

PV = nRT

Solve for V,

V = nRT / P

V = (5 * 62.363 * 393.15) / 1520

V = 80.65L

The volume the gas occupies is 80.65L

3 0

3 years ago

Convert 23 calories into kcal​

Convert 23 calories into kcal