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seropon [69]
3 years ago
13

What the answer I’m on a midterm and can’t seem to find it help

Chemistry
1 answer:
Sonja [21]3 years ago
8 0

Answer:

Sorry I’m not rlly sure but maybe the 2nd or the last

Explanation:

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What element does silver nitrate and sodium phosphate form when combined?
creativ13 [48]
AgNO3+Na3P04=Ag3PO4....
7 0
3 years ago
A 63 gram piece of magnesium absorbs 6689 joules of heat. The final temperature is 663 degrees Celsius. What was the initial tem
Gemiola [76]

Answer:

559^{\circ}C

Explanation:

When heat is supplied to a substance, the temperature of the substance increases according to:

Q=m C (T_f-T_i)

where

Q is the amount of heat supplied

m is the mass of the substance

C is the specific heat capacity of the substance

T_i is the initial temperature

T_f is the final temperature

For the sample of magnesium in this problem, we have:

m = 63 g is the mass

Q = 6689 J is the hear supplied

C = 1.023 J/gC is the specific heat capacity

T_f=663^{\circ}C is the final temperature

Solving the formula for T_i, we find the final temperature:

T_i = T_f-\frac{Q}{mC}=663-\frac{6689}{(63)(1.023)}=559^{\circ}C

6 0
3 years ago
Analysis of a rock sample shows that it contains 6.25% of its original uranium-235. How old is the rock? How do you know?
nadya68 [22]

Answer:

2.82\cdot 10^9 y

Explanation:

A radioactive isotope is an isotope that undergoes nuclear decay, breaking apart into a smaller nucleus and emitting radiation during the process.

The half-life of an isotope is the amount of time it takes for a certain quantity of a radioactive isotope to halve.

For a radioactive isotope, the amount of substance left after a certain time t is:

m(t)=m_0 (\frac{1}{2})^{\frac{t}{\tau}} (1)

where

m_0 is the mass of the substance at time t = 0

m(t) is the mass of the substance at time t

\tau is the half-life of the isotope

In this problem, the isotope is uranium-235, which has a half-life of

\tau=7.04\cdot 10^8 y

We also know that the amount of uranium left in the rock sample is 6.25% of its original value, this means that

\frac{m(t)}{m_0}=\frac{6.25}{100}

Substituting into (1) and solving for t, we can find how much time has passed:

t=-\tau log_2 (\frac{m(t)}{m_0})=-(7.04\cdot 10^8) log_2 (\frac{6.25}{100})=2.82\cdot 10^9 y

5 0
4 years ago
Using the following thermochemical data, what is the change in enthalpy for the following reaction: 3H2(g) + 2C(s) + ½O2(g) → C2
sweet [91]
It would be -277.6 KJ/mol
7 0
3 years ago
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Why is the ideal gas law useful although ideal gases do not exist
babymother [125]
I think it would be useful because then a gas station would have to save gas, instead of selling it all. But, for this question Im not to sure. Is this a multiple choice question_ 

8 0
3 years ago
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