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chubhunter [2.5K]
3 years ago
13

The jovian moon with the most geologically active surface is

Physics
1 answer:
m_a_m_a [10]3 years ago
6 0
<h2>Answer: Io </h2>

Io is the moon closest to Jupiter and is considered the most geologically active object in the solar system.

This is because very extensive plains rich in sulfur and sulfur dioxide, mountain ranges (mountains with an average height of about 6 km), and many volcanic formations on its surface have been observed.

As for the volcanoes, Io at least has many eruptions more or less continuous, which has very important effects on its topography, since the crust is in a process of constant renewal. This explains why no impact craters have been observed on its surface, as the continuous eruptions and lava flows cover them shortly after they occur.

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Which of the following would be the magnitude of the vector given a horizontal component of 30 and a
Scorpion4ik [409]

Answer:

50

Explanation:

Use the Pythagorean theorem to find the length of the diagonal, or the hypotenuse of an imaginary triangle. 30^2 + 40^2 = 2500, which is 50^2. So, the magnitude is 50.

Brainliest, please :)

7 0
1 year ago
When you catch a baseball, what kind of work do you do, negative or positive? By catching the baseball, what do you change? Does
bagirrra123 [75]
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3 0
3 years ago
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German physicist Werner Heisenberg related the uncertainty of an object's position (Δx) to the uncertainty in its velocity (Δ???
fredd [130]

Answer:

\Delta x = 5.47 \times 10^{-9} m

Explanation:

As we know by the principle of uncertainty that the product of uncertainty in position and uncertainty in momentum is given as

\Delta x \times \Delta P = \frac{h}{4\pi}

so here we know that

\Delta v = 0.01 \times 10^6 m/s

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so we have

\Delta x \times (9.11 \times 10^{-31})(0.01 \times 10^6) = \frac{6.26 \times 10^{-34}}{4\pi}

\Delta x = 5.47 \times 10^{-9} m

5 0
3 years ago
Lifting a box off the floor is an example of what type of force?
s2008m [1.1K]
Gravitational I think would be the answer, Hope this helps!
8 0
3 years ago
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How much time would it take for the sound of thunder to travel 1500 meters if sound travels at a speed of 330 m/s
Elis [28]

Data given:

Δx=1500m

v=330m/s

t=?

Formula:

V=Δx/t

Solution:

t=1500m/330m/s

t=4.5s

7 0
3 years ago
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