Moe is carrying and supporting a large crate by exerting 1000 N. He is walking at constant velocity across a level, horizontal f
1 answer:
To solve this problem it is necessary to apply the agreements related to Strength and Work.
Work is defined as the amount of energy required to move a force over a certain distance.
Where,
F = Force
d = distance
Our values are given as,
F = 1000N
d = 10m
Therefore replacing,
W = 1000*10
W = 10000J
Therefore the neccesary work is 10000J or 10kJ.
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Answer:
The Magnifying power of a telescope is
Explanation:
Radius of curvature R = 5.9 m = 590 cm
focal length of objective =
⇒ =
⇒ = 295 cm
Focal length of eyepiece = 2.7 cm
Magnifying power of a telescope is given by,
therefore the Magnifying power of a telescope is
To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,
Here,
m = Mass
V = Velocity
Replacing,
Therefore the final kinetic energy of the two car system is 72.6kJ