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Liono4ka [1.6K]
3 years ago
10

Moe is carrying and supporting a large crate by exerting 1000 N. He is walking at constant velocity across a level, horizontal f

loor. If he covers a distance of 10 meters, how much work does he do on the crate? Use g = 10m/s2 if needed. Ignore friction between Moe and the crate.
Physics
1 answer:
vivado [14]3 years ago
5 0

To solve this problem it is necessary to apply the agreements related to Strength and Work.

Work is defined as the amount of energy required to move a force over a certain distance.

W = F*d

Where,

F = Force

d = distance

Our values are given as,

F = 1000N

d = 10m

Therefore replacing,

W = 1000*10

W = 10000J

Therefore the neccesary work is 10000J or 10kJ.

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The car’s velocity at the end of this distance is <em>18.17 m/s.</em>

Given the following data:

  • Initial velocity, U = 22 m/s
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To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

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Substituting the values into the formula, we have;

V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}

<em>Final velocity, V = 18.17 m/s</em>

Therefore, the car’s velocity at the end of this distance is <em>18.17 m/s.</em>

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