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egoroff_w [7]
3 years ago
11

inside a wave describe the motion of water particles as the wave particles as the wave passes through​

Chemistry
1 answer:
Kipish [7]3 years ago
8 0

In a water wave all particles travel in clockwise circles.

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A rigid 3.80 L sealed vessel contains 0.650 mol Ne, 0.321 mol Kr, and 0.190 mol Xe. Find the density of the mixture in g/L.
Eddi Din [679]

Answer:

17.09g/L

Explanation:

Density = total mass of elements/ volume

We need to find the mass of each mixture constituents using their molar mass:

mole = mass/molar mass

For Neon (Ne) which contains 0.650mol;

0.650 = mass/20.18

mass = 0.650 × 20.18

mass = 13.12g

For Krypton (Kr) which contains 0.321mol;

0.321 = mass/83.79

mass = 0.321 × 83.79

mass = 26.89g

For Xenon (Xe) which contains 0.190mol;

0.190 = mass/131.3

mass = 0.190 × 131.3

mass = 24.95g

Total mass = 13.12g + 26.89g + 24.95g = 64.96g

Density = total mass / volume

Density = 64.96g / 3.80L

Density of the mixture = 17.09g/L

7 0
3 years ago
What is the role of our company compliance Department
kenny6666 [7]
<h3>A compliance department identifies risks that an organization faces and advises on how to avoid or address them.It implements controls to protect the organization from those risks.</h3>

Hope This Answer Helps.

6 0
2 years ago
How much more acidic/more H+ concentration is a pH of 6 than pH of 8
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Answer: 1000x

Explanation:

I hope this helped!

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2 years ago
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3 years ago
At high temperatures, sulfur combines with iron to form brown-black iron(II) sulfide:
taurus [48]

The percent yield : 79.9%

<h3>Further eplanation </h3>

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

Fe(s)+S(s)⇒FeS(s)

The reaction produces 6.29 g of iron(II) sulfide⇒an actual yield

The maximum  amount that can be produced is 7.87 g ⇒ A theoretical yield

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{6.29}{7.87}\times 100\5=79.9\%

3 0
3 years ago
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