How much energy is required to vaporize 0.5kg of water?
1 answer:
Answer:
Explanation:
Vaporization Equation => Q = m·ΔHv
m = 0.5Kg water = 500g water
ΔHv = Heat of vaporization = 540 calories/gram
∴Q = 500g x 540cal/g = 270,000 calories x 4.184 joules/cal = 1,129,680 joules = 1130 Kilojoules (3 sig. figs.)
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