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Pavlova-9 [17]
3 years ago
12

The Haber process is used to make ammonia, which is an important source of nitrogen that can be metabolized by plants. Using the

equation below, determine how many kilograms of ammonia will be formed from 89.5 kg of hydrogen. N2(g) + 3H2(g) → 2NH3(g)
Chemistry
1 answer:
Dimas [21]3 years ago
7 0

Answer:

506kg

Explanation:

From the reaction equation, we can see that 3 moles of hydrogen yielded 2 moles of ammonia.

Now we need to calculate the number of moles of hydrogen reacted. This mathematically equals the mass of hydrogen reacted divided by the molecular mass of the hydrogen molecule.

The mass of hydrogen reacted is 89.5kg. This equals 89.5 × 1000g which equals 89500g. The molecular mass of hydrogen is 2g/mole ( 1 atom of hydrogen has an atomic mass unit of 1 and 1 molecule of hydrogen has 2 atoms).

Now we mathematically calculate the number of moles of hydrogen reacted to be 89500/2 which equals 44,750 moles.

If 3 moles of hydrogen yielded 2 moles of ammonia gas, then 44, 750 moles will yield 44,750 × (2/3) which equals 29,833 moles of Ammonia gas.

Now, let's calculate the mass of Ammonia gas yielded. This mathematically equals the number of moles of ammonia gas yielded multiplied by the molar mass of ammonia gas. The molar mass of ammonia gas is (14 + 3(1)) which equals 17g/mole.

Hence, the mass yielded equals 29,833 × 17 = 506167g

This equals 506,167 ÷ 1000 = 506.167kg.

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What is the ratio of the areas of the signals in the h nmr spectrum of pentan-3-ol?
Damm [24]

The ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

<h3>What is a NMR spectrum?</h3>

Nuclear magnetic resonance spectroscopy is a spectroscopy that shows the detailed structure and chemical environment of a chemical element.

Pentan-3-ol contain 12 hydrogen atoms. In H-NMR spectra, hydrogen atoms have same environment gives a signal.

There are 4 different kinds of signals due of the 4 different environment experienced by these 12 hydrogens.

Thus, the  ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

Learn more about NMR spectrum

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8 0
2 years ago
The vapor pressure of liquid chloroform, CHCl3, is 100. mm Hg at 283 K. A 0.380 g sample of liquid CHCl3 is placed in a closed,
Katyanochek1 [597]

Answer:

a

No

b

100 mm Hg

Explanation:

From the question we are told that

The vapor pressure of CHCl3, is P = 100 \  mmHg =  \frac{100}{760}=  0.13156 \ atm

The temperature of CHCl3 is T  =  283 \  K

The volume of the container is V_c =  380mL =  380 *10^{-3}\  L

The temperature of the container is T_c  =  283 \  K

The mass of CHCl3 is m = 0.380 g

Generally the number of moles of CHCl3 present before evaporation started is mathematically represented as

n  =  \frac{m }{M }

Here M is the molar mass of CHCl3 with the value M  =  119.38 \ g/mol

=> n  =  \frac{ 0.380 }{119.38 }

=> n  =  0.00318 \  mols

Generally the number of moles of CHCl3 gas that evaporated is mathematically represented as

n_g  =  \frac{PV}{RT}

Here R is the gas constant with value R =  0.08206 L \  atm /mol\cdot  K

So

          n_g  =  \frac{0.13156* 380 *10^{-3} }{0.08206 * 283}

          n_g  =  0.00215 \  mols

Given that the number of moles of  CHCl3 evaporated is less than the number of moles of CHCl3  initially present , then it mean s that not all the liquid evaporated

At equilibrium the temperature of CHCl3 will be equal to the pressure of  air so the pressure at equilibrium is  100 mmHg

4 0
3 years ago
What would be the effect on your calculated mas percent recovery of Cu if you did not completely react the Mg in the reaction mi
Anarel [89]
The mass percentage would be reduced but not as much as if it were a complete reaction ヽ༼ຈل͜ຈ༽ノ︵┻━┻ mark brainliest please
6 0
3 years ago
How does the speed of a sound wave change based on the density of the medium the wave passes through?
Nikitich [7]

Answer:

i think its d i may be wrong

Explanation:

3 0
3 years ago
Read 2 more answers
N2 reacts with hydrogen gas according to the following equation:
slega [8]

Answer:

Mass = 51 g

Explanation:

Given data:

Mass of nitrogen = 41.93 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂      →       2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 41.93 g/ 28 g/mol

Number of moles = 1.5 mol

now we will compare the moles of nitrogen and ammonia.

                N₂          :           NH₃

                  1          :           2

                1.5         :         2/1×1.5 = 3 mol

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 3 mol × 17 g/mol

Mass = 51 g

6 0
3 years ago
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