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Dahasolnce [82]
3 years ago
7

When would you need the fight or flight response?

Chemistry
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

When you have the feeling of danger and you either don't want to face it or you want to face it.

Explanation:

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Help me please and ty
satela [25.4K]

Answer:

it the same side with the other side you fellow the other side

Explanation:

7 0
3 years ago
Read 2 more answers
When an aqueous solution of sodium phosphate (Na3PO4) and an aqueous solution of magnesium sulfate (MgSO4) are mixed, a precipit
Akimi4 [234]

Answer: The chemical formula of this precipitate is Mg_{3}(PO_{4})_{2}.

Explanation:

An equation which depicts the chemical reaction of substances in the form of chemical formulas is called a chemical equation.

For example, chemical equation for an aqueous solution of sodium phosphate (Na_{3}PO_{4}) and an aqueous solution of magnesium sulfate (MgSO_{4}) are mixed, a precipitate forms is as follows.

3MgSO_{4}(aq) + 2Na_{3}PO_{4}(aq) \rightarrow Mg_{3}(PO_{4})_{2}(s) + 3Na_{2}SO_{4}(aq)

Here, trimagnesium phosphate is the precipitate. The chemical formula of this precipitate is Mg_{3}(PO_{4})_{2}.

Thus, we can conclude that the chemical formula of this precipitate is Mg_{3}(PO_{4})_{2}.

8 0
3 years ago
PLEASE HELP
neonofarm [45]

Answer:

The answer to your question is 0.10 M

Explanation:

Data

Molarity = ?

mass of Sucrose = 125 g

volume = 3.5 l

Formula

Molarity = moles / volume

Process

1.- Calculate the molar mass of sucrose

C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

               = 144 + 22 + 176

               = 342 g

2.- Convert the mass of sucrose to moles

                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

                           x = (125 x 1) / 342

                           x = 0.365 moles

3.- Calculate the molarity

Molarity = 0.365 / 3.5

4.- Result

Molarity = 0.10

5 0
3 years ago
Many chemical names are similar at first glance. Give the formulas of the species in each set: (a) ammonium ion and ammonia; (b)
ohaa [14]

Answer:

a) Ammonium ion: NH₄⁺, ammonia: NH₃.

b)Magnesium sulfide: MgS, magnesium sulfite: MgSO₃, magnesium sulfate: MgSO₄.

c) Chloric acid: HClO₃, chlorous acid HClO₂.

d) Cupric bromide: CuBr₂, cuprous bromide: CuBr.

Explanation:

a) Ammonia is the neutral substance, which as molecular formula NH₃ when it gains a proton, it becomes the ammonium ion NH₄⁺.

b) In the name of salts, first, it comes the cation name, in this case, all the cations are the magnesium (Mg²⁺). The ions of sulfur can be oxidized or not, the termination "ide" indicates the non-oxidized ion (S⁻²), "ite" the less oxidized (SO₃⁻²), and "ate" the more oxidized (SO₄⁻²). To do the molecular formula, the charges are replaced without the signals and put down. If they are equal, the number is not put.

Magnesium sulfide: MgS

Magnesium sulfite: MgSO₃

Magnesium sulfate: MgSO₄

c) The acids can be oxidized or not, when it has no oxygens, the name is given "hydro" + the anion name, as hydrochloric acid (HCl). When there's oxygen in the molecule, the more oxidized is name as "'per" + anion name + "ic", the second more oxidized as anion name + "ic", the second less oxidized as anion name + "us", and the less oxidized as "hypo" + anion name + "us". In this case:

chloric acid: HClO₃

chlorous acid HClO₂

d) The salts of copper are named depends on the oxidation number of the cupper. The one with a higher oxidation number( +2) is called cupric, and the other (+1), cuprous. Thus:

cupric bromide: CuBr₂ (oxidation number = +2)

cuprous bromide: CuBr (oxidation number = +1)

5 0
3 years ago
Read 2 more answers
Please help correct answers only please
faltersainse [42]

Answer:

Empirical formula is C₅H₁₂O

Molecular formula = C₅H₁₂O

Explanation:

Given data:

Percentage of hydrogen =13.75%

Percentage of carbon = 68.11%

Percentage of oxygen = 18.15%

Empirical formula = ?

Solution:

Number of gram atoms of H = 13.75 / 1.01 = 13.6

Number of gram atoms of O = 18.15 / 16 = 1.13

Number of gram atoms of C = 68.11 / 12 = 5.68

Atomic ratio:

            C                      :      H               :         O

           5.68/1.13           :     13.6/1.13     :       1.13/1.13

            5                      :        12          :        1

C : H : O = 5 : 12 : 1

Empirical formula is C₅H₁₂O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass :

5×12 + 12×1.01 + 16×1 = 88.12 g/mol

n = 88.17/ 88.12

n = 1

Molecular formula = n (empirical formula)

Molecular formula = 1 (C₅H₁₂O)

Molecular formula = C₅H₁₂O

8 0
3 years ago
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