Answer:
a. V_y = 50m/s and V_x = 86.6m/s
b. d_x = 173.2m
c. d_y = 80.38m
Explanation:
V_x = 100m/s*cos(30°)
V_x = 86.6m/s
V_y = 100m/s*sin(30°)
V_y = 50m/s
D_x = v_x*t
d_x = 86.6m/s*2s
d_x = 173.2m
v_f = 50m/s+(-9.81m/s²)*2s
v_f = 30.38m/s
d_y = .5*(30.38m/s+50m/s)*2s
d_y = 80.38m
Answer:
(A) COP = 2.64
(B) rate of heat absorption= 1.9637 kW
Explanation:
mass flow rate (m) = 0.018 kg/s
work input (Win) = 1.2kW
inlet pressure (P1) = 800kPa
inlet temperature (T1) = 35 degree Celsius
h1 = 271.24 KJ/Kg
outlet pressure (P2) = 800 kPa
outlet temperature (T2) = ?
entalphy (h2) = 95.48 KJ/Kg
The entalphies are gotten from tables for refrigerant 134a at the temperatures and pressures above
(A) COP = Qh ÷ Win
where Qh = m(h1 -h2) from the energy balance equation
Qh = 0.018 ( 271.24 - 95.48 ) = 3.1637 kW
COP = 3.1637 ÷ 1.2 = 2.64
(B) rate of heat absorption = Qh - Win
= 3.1637 - 1.2 = 1.9637 kW
Answer:
Positive
Explanation:
Tbh I dont have an explanation I just wanted to give the answer but its for sure correct!
The O2 sensor<span> does produce its own voltage,</span>but<span> there are also two wires.</span>
<span>The sum of the protons and neutrons in an atom equals the mass number. </span>
