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a_sh-v [17]
3 years ago
5

A player hits a ball with a bat. The action force is the impact of the bat against the ball. The reaction to this force is the

Physics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

Force of the ball against the bat

Explanation:

Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.

                             F_{A} = - F_{B}

Where;

F_{A} is the action force of the bat against the ball.

F_{B} is the equal and opposite reaction force of the ball towards the ball.

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While plane is moving under tailwind condition it took time "t"

so here we will have

t = \frac{d}{v_{net}}

here net speed of the plane will be given as

v_{net} = v + v_w

t = \frac{1000}{205 + v_w}

similarly when it moves under the condition of headwind its net speed is given as

v_{net} = v - v_w

now time taken to cover the distance is 2 hours more

t + 2 = \frac{1000}{205 - v_w}

now solving two equations

\frac{1000}{205 + v_w} + 2 = \frac{1000}{205 - v_w}

solving above for v_w we got

v_w = 40.4 mph

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3 years ago
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Answer:

it means the velocity is changing.

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DaniilM [7]

Answer:

Current would decrease 9 times.

Explanation:

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\frac{I_1}{I_2} = \frac{U/R_1}{U/R_2} = \frac{U}{U}\frac{R_2}{R_1} = \frac{\rho L/A_2}{\rho L / A_1} = \frac{\rho L}{\rho L}\frac{A_1}{A_2} = \frac{\pi d_1^2/4}{\pi d_2^2/4} = \frac{4\pi}{4\pi}\left(\frac{d_1}{d_2}\right)^2 = 3^2 = 9

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Radda [10]

Answer:

Some current is lost.

Explanation:

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