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3 years ago

Calculate the moles of SO2 that contains 3.8 moles of O atoms

1 answer:

5 0

Answer: 1.9 moles SO₂

Explanation:

1) The chemical formula SO₂ shows that for every mol of SO₂ there are 1 mol of S and two moles of O.

2) Then you can state the proportion between the number of moles of SO₂ and O to find how many moles of SO₂:contains 3.8 moles of O.

   1 mol SO₂                         x

-------------------- =   --------------------------

    2 moles O              3.8 moles O

3) Now, you can clear x:

x = 3.8 moles O × 1 mol SO₂ / 2 moles O.

x = 1.9 moles SO₂.

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The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

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6 0

3 years ago

Can someone help me please ?

KiRa [710]

Answer: B

Explanation:

Graph 1 represents an endothermic reaction, Graph 2 represents an exothermic reaction.

***If you found my answer helpful, please give me the brainliest. :) ****

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3 years ago

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alex41 [277]

Answer:

False

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2 years ago

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3 years ago

In an chemicalbreaction involving Fe and S, it was found that 45.2 g of Fes was produced. If the percent yield of the reaction i

saw5 [17]

Answer:

47.8 g

Explanation:

Remember the equation for percent yield:

% yield = actual / theoretical

We're given two of the values in the question, so plug n' play:

0.945 = 45.2 / theoretical

theoretical = 47.8 g

Keep in mind you can use mass here without converting to moles because we're working with products only. If you were given a mass of reactants, you would need to convert to moles and using a balanced chemical equation find the corresponding moles of product produced.

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3 years ago