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1 year ago

Which is the following is a decomposition reaction

Chemistry

1 answer:

lora16 [44]1 year ago

5 0

The equation that is a decomposition reaction is

PbCO3(s) ---> PbO(s) + CO2(g)

That is option D.

<h3>Properties of a decomposition reaction</h3>

A chemical reaction is defined as the combination of substances called reactants to form a product. The various types of chemical reaction include:

synthesis reaction

combustion reaction

decomposition reaction

single or double replacement reaction

Decomposition reaction is that type of chemical reaction in which the reactant breaks down to form two or more products.

Therefore the heating of lead (II) carbonate is a decomposition reaction.

Learn more about decomposition reaction here:

brainly.com/question/15229375

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Some amount of hydrogen peroxide (H2O2) breaks down to produce 3 molecules of oxygen (O2) and 6 molecules of water (H2O). How ma

soldier1979 [14.2K]

Answer:

$Atoms_H=12Atoms$

Explanation:

Hello,

In this case, the only source of hydrogen is in the 6 molecules of water, therefore, the atoms of hydrogen, by applying stoichiometry with the Avogadro's number is:

$Atoms_H=6moleculesH_2O*\frac{1molH_2O}{6.022x10^{23}moleculesH_2O}\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}AtomsH}{1molH} \\Atoms_H=12Atoms$

Best regards.

3 0

2 years ago

Read 2 more answers

BRAINLIEST ASAP

Sveta_85 [38]

The first three quantum numbers for electrons located in subshell 4s are :

n = 4

l = 0

m = 0

3 0

2 years ago

Consider the balanced equation for the following reaction:

Bad White [126]

<u>Answer:</u> The theoretical yield of the lithium chlorate is 1054.67 grams

<u>Explanation:</u>

To calculate the mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Actual moles of lithium chlorate = 9.45 moles

Molar mass of lithium chlorate = 90.4 g/mol

Putting values in above equation, we get:

$9.45mol=\frac{\text{Actual yield of lithium chlorate}}{90.4g/mol}\\\\\text{Actual yield of lithium chlorate}=(9.45mol\times 90.4g/mol)=854.28g$

To calculate the theoretical yield of lithium chlorate, we use the equation:

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

Actual yield of lithium chlorate = 854.28 g

Percentage yield of lithium chlorate = 81.0 %

Putting values in above equation, we get:

$81=\frac{854.28g}{\text{Theoretical yield of lithium chlorate}}\times 100\\\\\text{Theoretical yield of lithium chlorate}=\frac{854.28\times 100}{81}=1054.67g$

Hence, the theoretical yield of the lithium chlorate is 1054.67 grams

7 0

2 years ago

What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol

ad-work [718]

Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

molar mass of NaCl = 58.44 g/mol

moles of NaCl = 63 g * 1 mol/(58.44 g)

moles of NaCl = 1.078 moles

Finally we can find the molarity of the solution

molarity = moles of NaCl/(volume of solution)

molarity = 1.078 moles/(0.65 L)

molarity = 1.66 M

Answer: the molarity of the solution is 1.66 M.

7 0

6 months ago

What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F

AnnyKZ [126]

<u>Answer:</u> The chemical formula of Iron (III) sulfate is $Fe_2(SO_4)_3$

<u>Explanation:</u>

Iron is the 26th element of periodic table having electronic configuration of $[Ar]3d^64s^2$ .

To form $Fe^{3+}$ ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of $SO_4^{2-}$

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is $Fe_2(SO_4)_3$

4 0

2 years ago