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AlexFokin [52]
3 years ago
10

What are 2 ways acceleration can be changed?

Physics
1 answer:
lions [1.4K]3 years ago
3 0
2 Ways Acceleration can be changed are:

i) Increasing or decreasing the velocity of a moving object.

ii) Change of direction of the moving object.
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The change in electric potential energy per unit charge is
klemol [59]

D-Volatge / gravity and current aren’t units and amperes is the loop of electrical current

6 0
3 years ago
Read 2 more answers
5) Sally has a mass of 50 kg. She ran with a velocity of 20 m/s.
Ket [755]

Answer:

<h2>10,000 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2} \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 50 \times  {20}^{2}  \\  = 25 \times 400 \\  = 10000

We have the final answer as

<h3>10,000 J</h3>

Hope this helps you

7 0
2 years ago
PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
AleksAgata [21]
22. a - (vf^2 - vi^2)/(2d) 
a = (0 - 23^2)/(170) 
a = -3.1 m/s^2

23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3 
33 = 3t 
t = 11 sec to reach 33 m/s^2
Find the av velocuty: 33+0/2 = 16.5 m/s
Dist = 16.5 * 11 = 181.5 meters to each 33m/s speed. Runway has to be at least this long. 

24. The sprinter starts from rest. The average acceleration is found from: 
(Vf)^2 = (Vi)^2 = 2as ---> a = (Vf)^2 - (Vi)^2/2s = (11.5m/s)^2-0/2(15.0m) = 4.408m/s^2 estimated: 4.41m/s^2
The elapsed time is found by solving
Vf = Vi + at ----> t = vf-vi/a = 11.5m/s-0/4.408m/s^2 = 2.61s

25. Acceleration of car = v-u/t = 0ms^-1-21.0ms^-1/6.00s = -3.50ms^-2
S = v^2 - u^2/2a = (0ms^-1)^2-(21.0ms^-1)^2/2*-3.50ms^-2 = 63.0m 

26. Assuming a constant deceleration of 7.00 m/s^2
final velocity, v = 0m/s 
acceleration, a = -7.00m/s^2
displacement, s - 92m 
Using v^2 = u^2 - 2as 
0^2 - u^2 + 2 (-7.00) (92) 
initial velocity, u = sqrt (1288) = 35.9 m/s 
This is the speed pf the car just bore braking. 

I hope this helps!! 

5 0
3 years ago
Help ME QUICK PLEASE QUESTION 2 AND 4 PLEASE 58 POINTS
monitta

Answer:

For number 4: A vector pointing to the right with a magnitude of 2.0

Explanation:

Very simple- just subtract 6-2

I am not sure how to do #2- sorry!

6 0
3 years ago
What are some of the difficulties with measuring the volume of a gas? Select all that apply.
forsale [732]

Answer:

it is ---D because you can't measure gas and it's mass

HOPE THIS HELPS

6 0
3 years ago
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