Answer:
3/7 ω
Explanation:
Initial momentum = final momentum
I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet
-Iω + 6Iω - 2Iω = 7I ωnet
3Iω = 7I ωnet
ωnet = 3/7 ω
The final angular velocity will be 3/7 ω counterclockwise.
 
        
                    
             
        
        
        
Answer:
Explanation:
Here image distance is fixed .
In the first case if v be image distance 
1 / v - 1 / -25 = 1 / .05 
1 / v = 1 / .05 - 1 / 25 
= 20 - .04 = 19.96 
v = .0501 m = 5.01 cm 
In the second case 
u = 4 , 
1 / v - 1 / - 4 = 1 / .05 
1 / v = 20 - 1 / 4 = 19.75 
 v = .0506 = 5.06 cm 
So lens must be moved forward by 5.06 - 5.01 =  .05 cm ( away from film )
 
        
             
        
        
        
Answer:
the angular velocity of the car is 12.568 rad/s.
Explanation:
Given;
radius of the circular track, r = 0.3 m
number of revolutions  per second made by the car, ω = 2 rev/s
The angular velocity of the car in radian per second is calculated as;
From the given data, we convert the angular velocity in revolution per second to radian per second.

Therefore, the angular velocity of the car is 12.568 rad/s.
 
        
             
        
        
        
D. The man's traits (ff) would be recessive and with one of the girls (FF), all their offspring would have the genotype Ff, meaning all the offspring have freckles.