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3 years ago

Please i need help! ill give brainliest toooo!

Physics

2 answers:

Igoryamba3 years ago

7 0

Answer:

Explanation:

Mariana [72]3 years ago

5 0

Answer:

Explanation:

Plasmas are similar to gasses in terms of shape and volume. The only difference between gasses and plasma is that plasma conducts electricity.

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0.0084x91 ...................

Drupady [299]

Answer:

0.0084×91=0.7644

Explanation:

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8 0

3 years ago

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Một nhà máy điện hơi nước nhận nhiệt từ một lò nung với tốc độ 280(gj/h) . Tổn thất nhiệt cho không khí xung quanh khi nó đi qua

weeeeeb [17]

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6 0

3 years ago

A batter swings at a baseball. The action force is the bat hitting the ball with a force of 5N. The reaction force, however, can

dlinn [17]

This is false. The reaction force can be determined.

6 0

3 years ago

PLZ ANSWER ASAP!!!!!!!

jenyasd209 [6]

Explanation:

It is given that,

Mass of platinum bar, m = 750 g

Length of the bar, l = 5 cm

Breadth of the bar, b = 4 cm

Width of the bar, h = 1.5 cm

Volume of the bar, $V=l\times b\times h$

$V=5\times 4\times 1.5=30\ cm^3$

We need to find the density of the platinum bar. The density of any substance is given by :

$d=\dfrac{m}{V}$

$d=\dfrac{750\ g}{30\ cm^3}$

$d=25\ g/cm^3$

So, the density of the platinum bar $25\ g/cm^3$ . Hence, this is the required solution.

4 0

3 years ago

: Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at

ser-zykov [4K]

Complete Question

Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at sea level. One container is in Denver at an altitude of about 6,000 ft and the other is in New Orleans (at sea level). The surface area of the container lid is A=0.0155 m. The air pressure in Denver is PD = 79000 Pa. and in New Orleans is PNo = 100250 Pa. Assume the lid is weightless.

Part (a) Write an expression for the force FNo required to remove the container lid in New Orleans.

Part (b) Calculate the force FNo required to lift off the container lid in New Orleans, in newtons.

Part (c) Calculate the force Fp required to lift off the container lid in Denver, in newtons.

Part (d) is more force required to lift the lid in Denver (higher altitude, lower pressure) or New Orleans (lower altitude, higher pressure)?

Answer:

The expression is $F_{No} = A [P_{No} - \frac{P_{sea}}{2}]$

$F_{No}= 7771.125 \ N$

$F_p = 2.2*10^{6} N$

From the value obtained we can say the that the force required to open the lid is higher at Denver

Explanation:

The altitude of container in Denver is $d_D = 6000 \ ft = 6000 * 0.3048 = 1828.8m$

The surface area of the container lid is $A = 0.0155m^2$

The altitude of container in New Orleans is sea-level

The air pressure in Denver is $P_D = 79000 \ Pa$

The air pressure in new Orleans is $P_{ro} = 100250 \ Pa$

Generally force is mathematically represented as

$F_{No} = \Delta P A$

So we are told the pressure inside is is half the pressure the at sea level so the the pressure acting on the container would

The pressure at sea level is a constant with a value of

$P_{sea} = 101000 Pa$

So the $\Delta P$ which is the difference in pressure within and outside the container is

$\Delta P = P_{No} - \frac{P_{sea}}{2}$

Therefore

$F_{No} = A [P_{No} - \frac{P_{sea}}{2}]$

Now substituting values

$F_{No} = 0.0155 [100250 - \frac{101000}{2}]$

$F_{No}= 7771.125 \ N$

The force to remove the lid in Denver is

$F_p = \Delta P_d A$

So we are told the pressure inside is is half the pressure the at sea level so the the pressure acting on the container would

The pressure at sea level is a constant with a value of

$P_{sea} = 101000 Pa$

At sea level the air pressure in Denver is mathematically represented as

$P_D = \rho g h$

=> $g = \frac{P_D}{\rho h}$

Let height at sea level is h = 1

The air pressure at height $d_D$

$P_d__{D}} = \rho gd_D$

=> $g = \frac{P_d_D}{\rho d_D}$

Equating the both

$\frac{P_D}{\rho h} = \frac{P_d_D}{\rho d_D}$

$P_d_D = P_D * d_D$

Substituting value

$P_d__{D}} = 1828.2 * 79000$

$P_d__{D}} = 1.445*10^{8} Pa$

$\Delta P_d = P_{d} _D - \frac{P_{sea}}{2}$

=> $\Delta P_d = 1.445 *10^{8} - \frac{101000}{2}$

$\Delta P_d = 1.44*10^{8}Pa$

$F_p = \Delta P_d A$

$= 1.44*10^8 * 0.0155$

$F_p = 2.2*10^{6} N$

6 0

4 years ago