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laila [671]
2 years ago
14

Please i need help! ill give brainliest toooo!

Physics
2 answers:
Igoryamba2 years ago
7 0

Answer:

b

Explanation:

Mariana [72]2 years ago
5 0

Answer:

B

Explanation:

Plasmas are similar to gasses in terms of shape and volume.  The only difference between gasses and plasma is that plasma conducts electricity.

Consider giving brainliest?

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Jodi made a list about electric current to help her study for a test. 1) Movement of electrons is continuous in a current. 2) El
Vladimir79 [104]

Answer:

Rate at which current flows is measured in amperes

Explanation:

The rate of flow of electrons constitutes the current. The electrons flow from lower electric potential to higher electric potential. When there is no potential difference then no electron will flow. The direction of the current and the electron are in opposite direction.

The direction of electron from the negative terminal to the positive terminal. The direction of current is from the positive terminal to the negative terminal.The current is measured in ampere.    

The expression for current and the charge is as;

I=\frac{q}{t}

Here, q is the charge, t is the time taken and I is the current.

According to the given problem, Jodi made a list about electric current to help her study for a test. He described that electrons move from areas of low to high electric potential, voltage causes current to flow and movement of electrons is continuous in a current.

But he did error. It should be "rate at which charges flow" instead of rate at which current flow.

Therefore, the option (4) is correct.

4 0
3 years ago
Read 2 more answers
What is the station's orbital speed? the radius of earth is 6.37×106m, its mass is 5.98×1024kg.
Paha777 [63]

Answer:

v_o=2503.08\frac{m}{s}

Explanation:

Orbital velocity is the speed that a body that orbits around another body must have, for its orbit to be stable. For orbits with small eccentricity and when one of the masses is almost negligible compared to the other mass, like in this case, the orbital speed is given by:

v_o=\sqrt{\frac{GM}{r}}

Where M is the greater mass around which this negligible body is orbiting, r is the radius of the greater mass and G is the universal gravitational constant. So:

v_o=\sqrt{\frac{6.674*10^{-11}\frac{m^3}{kg\cdot s^2}(5.98*10^{24}kg)}{6.37*10^6m}}\\v_o=2503.08\frac{m}{s}

3 0
2 years ago
Read 2 more answers
¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!
asambeis [7]

Answer:

(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C

Explanation:

(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J

The electric potential is given by

W = q V

40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V

(b)

charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m

Let the potential is V.

V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V

(c)

Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V

Let the charge is q.

W= q V

8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C

3 0
2 years ago
You are approaching a helicopter on a helipad in an ambulance. The helicopter is powered down and the blades are not spinning. A
Maksim231197 [3]

After notifying the PIC of your arrival, it is best to approach the sides of the helicopter in this scenario.

<h3>What is an Ambulance?</h3>

This is a vehicle which contains medical equipments and are involved in the transportation of patients to healthcare facilities.

It is best to approach the sides of the helicopter and not tail rotor end to ensure visibility and safety.

Read more about Ambulance here brainly.com/question/16612316

#SPJ1

7 0
1 year ago
The water flowing through a 2.0 cm (inside diameter) pipe flows out through three 1.3 cm pipes. (a) If the flow rates in the thr
Verdich [7]

Answer:

a)54L/min

b)0.845

Explanation:

a) A x V=A_1V_1+ A_2V_2+A_3V_3

where suffix 1,2,3 refers to the three pipes.

            =27L/min+16L/min+11 L/min

            =54L/min

b) A x V=54L/min => \frac{\pi }{4} d^2 x v

   d= 2 cm

\frac{\pi }{4} d^2 x v = 54

v= \frac{4}{\pi } x \frac{54}{2^2}

-> A_1 x V_1=27L/min => \frac{\pi }{4} d_1^2 x v_1

d_1= 1.3cm

\frac{\pi }{4} d^2 x v_1 = 27

v_1= \frac{4}{\pi } x \frac{27}{1.3^2}

Next is to find the ratio of speed i.e \frac{v}{v_1}

\frac{4}{\pi } x \frac{54}{2^2} / \frac{4}{\pi } x \frac{27}{1.3^2} => \frac{54}{27} \frac{1.3^2}{2^2}

\frac{v}{v_1}= 0.845

8 0
2 years ago
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