Any solute that dissolves in water to give a solution that contains ions, and which therefore conducts electricity, is called an electrolyte. On the other hand, a solute that remains undissociated in solution is called a nonelectrolyte.
The new volume : V₂ = 2454.8 L
<h3>Further explanation</h3>
Given
V₁=2240 L
P₁=760 mmHg
T₁=320 K
P₂=700 mmHg
T₂=323 K
Required
Volume V₂
Solution
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
760 mmHg x 2240 L /320 K = 700 mmHg x V₂/323 K
V₂=(P₁V₁T₂)/P₂T₁
V₂=(760 x 2240 x 323)/(700 x 320)
V₂ = 2454.8 L
Newton's first law of motion predicts the behavior of objects where all existing forces are balanced. Objects at equilibrium will not accelerate. Also, an object will only accelerate if there is a net or unbalanced force acting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.
Newton's second law of motion: behavior of objects for and all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
The amount of heat energy added to silver to heat it from 25°C to 100°C is :
8737.5 J
<u>Given data: </u>
mass of silver ( m ) = 500 g
T1 = 25°C
T2 = 100°C
s ( specific heat of silver ) = 0.233 J/g.c
<h3 /><h3>Determine the amount of heat required </h3>
Applying the formula below for heat ( Q )
Q = ms * ΔT
= 500 * 0.233 * ( 100 - 25 )
= 8737.5 J
Hence we can conclude that the The amount of heat energy added to silver to heat it from 25°C to 100°C is : 8737.5 J.
Learn more about heat energy : brainly.com/question/13439286
<span>1,3-cylohexadiene i synthesized starting from cyclohexane in following 4 steps.
1) Free Radical Substitution Rxn: Halogenation of cyclohexane in the presence of UV yield chlorocyclohexane.
2) Elimination Rxn: Dehydrohalogenation of chlorocyclohexane yields cyclohexene.
3) Halogenation of Cyclohexene (
Electrophillic Addition Rxn) gives 1,2-dihalocyclohexane.
4) Elemination Rxn: When dibromocyclohexane is treated with KOH and heated it gives 1,3-cyclohexadiene as shown below,</span>