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3 years ago

The highest tides of the year are neap tides. True False

Chemistry

2 answers:

just olya [345]3 years ago

8 0

I think its false...

Ilya [14]3 years ago

8 0

<h3><em>It is FALSE that highest tides of the year are neap tides.</em></h3>

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For 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g), if you begin with 16.00 g ammonia and excess oxygen, how many grams of water will be ob

iragen [17]

12.7 grams approximately

8 0

3 years ago

A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

Zarrin [17]

Answer: Empirical formula is $C_2H_5O$

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = $\frac{330g}{12g/mol}=27.5moles$

Moles of Hydrogen = $\frac{69.5g}{1g/mol}=69.5moles$

Moles of Oxygen = $\frac{220.2g}{16g/mol}=13.76moles$

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

$\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2$

$\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5$

$\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1$

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = $C_2H_5O$

7 0

3 years ago

20. A compound's empirical formula is C,H,O. If the molecular mass of the compound is

kozerog [31]

Answer:

Just use a text book.. So that you get the concept

6 0

3 years ago

If the pressure on a gas at -73°C is doubled but its volume is held constant, what will its final temperature be in degrees Cels

Gre4nikov [31]

Answer:

127°C

Explanation:

This excersise can be solved, with the Charles Gay Lussac law, where the pressure of the gas is modified according to absolute T°.

We convert our value to K → -73°C + 273 = 200 K

The moles are the same, and the volume is also the same:

P₁ / T₁ = P₂ / T₂

But the pressure is doubled so: P₁ / T₁ = 2P₁ / T₂

P₁ / 200K = 2P₁ / T₂

1 /2OOK = (2P₁ / T₂) / P₁

See how's P₁ term is cancelled.

200K⁻¹ = 2/ T₂

T₂ = 2 / 200K⁻¹ → 400K

We convert the T° to C → 400 K - 273 = 127°C

4 0

3 years ago

What is the magnitude of the vector described below?

photoshop1234 [79]

There are two types of 'quantities' namely: scalar and vector

A 'vector' is a quantity that has both magnitude and direction whereas a 'scalar' has only magnitude.

Magnitude is a measure or the size of the quantity or object.

In the given example of the vector: '75 mph to the north'

Magnitude is the number 75 mph

Direction is north

Ans C)

3 0

3 years ago

Read 2 more answers