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PolarNik [594]
3 years ago
7

The limiting reactant in a reaction a. is the reactant for which there is the least amount in grams b. is the reactant which has

the lowest coefficient in a balanced equation c. is the reactant for which there is the most amount in grams d. is the reactant for which there is the fewest number of moles e. none of the above
Chemistry
1 answer:
Shalnov [3]3 years ago
5 0

Actually the correct answer must be:

The limiting reactant in the reaction is the one which has the lowest ratio of moles available over coefficient in the balanced equation

 

This is because the actual mass or number of moles of the reactant does not directly dictate if it is a limiting reactant, this must be relative to the other reactants.

 

So the answer is:

e. none of the above

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HELP - a solution NaOCl was prepared at pH 10.3. calculate the concentration of the salt formed. Given Ka for HOCl=3.0x10^-8
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First we dissociate the salt

NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]

note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.

OCl⁻ + H₂O ⇄ OH⁻ + HOCL

<span>Ka for HOCl = 3.0x10^-8, therefore

Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
                       = 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
                       = 3.3 × 10⁻⁷

</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]

convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴

set up equib table

          OCl⁻                + H₂O    ⇄      OH⁻        +           HOCl
  ST     x                                               0                             0
 +Δ    -1.995 × 10⁻⁴                   +1.995 × 10⁻⁴        +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
 EQ:   x -1.995 × 10⁻⁴                 1.995 × 10⁻⁴          1.995 × 10⁻⁴

Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]

The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M

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