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makkiz [27]
2 years ago
6

Can some one please help to understand this problem??​

Chemistry
1 answer:
Rama09 [41]2 years ago
6 0

Answer:

mercury, magnesium, water and gasoline.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

The liquid with higher density will sink in bottom while the liquid with lower density will float.

In given samples,

density of water = 1 g/mL

density of mercury = 13.6 g/mL

density of gasoline = 0.70 g/mL

density of magnesium = 1.7 g/mL

So on the basis of given density values mercury will sink in bottom then above it magnesium will present than water and above on these three gasoline will present.

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Prove that PV = nRT.​
qaws [65]

Find your answer in the explanation below.

Explanation:

PV = nRT is called the ideal gas equation and its a combination of 3 laws; Charles' law, Boyle's law and Avogadro's law.

According to Boyle's law, at constant temperature, the volume of a gas is inversely proportional to the pressure. i.e V = 1/P

From, Charles' law, we have that volume is directly proportional to the absolute temperature of the gas at constant pressure. i.e V = T

Avogadro's law finally states that equal volume of all gases at the same temperature and pressure contain the same number of molecules. i.e V = n

Combining the 3 Laws together i.e equating volume in all 3 laws, we have

V = nT/P,

V = constant nT/P

(constant = general gas constant = R)

V = RnT/P

by bringing P to the LHS, we have,

PV = nRT.

Q.E.D

6 0
2 years ago
The conversion of cyclopropane to propene occurs with a first-order rate constant of . How long will it take for the concentrati
Gennadij [26K]

This is an incomplete question, here is a complete question.

The conversion of cyclopropane to propene occurs with a first-order rate constant of 2.42 × 10⁻² hr⁻¹. How long will it take for the concentration of cyclopropane to decrease from an initial concentration 0.080 mol/L to 0.053 mol/L?

Answer : The time taken will be, 17.0 hr

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 2.42\times 10^{-2}\text{ hr}^{-1}

t = time passed by the sample  = ?

a = initial concentration of the reactant  = 0.080 M

a - x = concentration left = 0.053 M

Now put all the given values in above equation, we get

t=\frac{2.303}{2.42\times 10^{-2}}\log\frac{0.080}{0.053}

t=17.0\text{ hr}

Therefore, the time taken will be, 17.0 hr

5 0
3 years ago
Why do scientists think there is an undiscovered carbon sink somewhere?
dedylja [7]
The major carbon sources (reservoirs that release more carbon than absorbed) are: deforestation and fossil fuels

The major carbon sinks (reservoirs that absorb more carbon than released) are:
soil, oceans and plants.

When scientists calculate the amount of carbon dioxide is returned to the atmosphere vs the released the amount of carbon, a large amount is unaccounted for and the total does not add up. This is why scientists believe there is an undiscovered carbon sink somewhere.
6 0
3 years ago
Read 2 more answers
An unsaturated solution has,
olganol [36]

Answer:

D... I think? Because it is unsaturated so there is more solute than solvent...

8 0
2 years ago
Read 2 more answers
At constant temperature, a sample of helium at 760. torr in a closed container was compressed 5) from 5.00 L to 3.00 L, with no
jek_recluse [69]

Answer:

B) 1270 torr

Explanation:

Given data

  • Initial volume (V₁): 5.00 L
  • Initial pressure (P₁): 760 torr
  • Final volume (V₂): 3.00 L
  • Final pressure (P₂): ?

We can find the final pressure using Boyle's law.

P₁ × V₁ = P₂ × V₂

P₂ = P₁ × V₁/V₂

P₂ = 760 torr × 5.00 L/3.00 L

P₂ = 1.27 × 10³ torr = 1270 torr

The final pressure is 1270 torr.

5 0
3 years ago
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