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nexus9112 [7]
3 years ago
7

What is Gallium Nitrite

Chemistry
2 answers:
olganol [36]3 years ago
8 0
It is a binary direct bandgap semiconductor commonly used in light-emitting diodes since the 1990s
Shtirlitz [24]3 years ago
8 0
<span>Formula= GaN 
Ga = 31 
N = 7
.........</span>
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Explain how are elements classified and provide an example
swat32
By nonmetals, metals, and gases
4 0
3 years ago
Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of n-propanol (C3H7OH)is burned in air, -33.4 kJ of hea
Inga [223]

Answer : The heat of combustion of n-propanol is 0.554 kJ/mol

Explanation :

First we have to calculate the moles of n-propanol.

\text{Moles of n-propanol}=\frac{\text{Mass of n-propanol}}{\text{Molar mass of n-propanol}}

Molar mass of n-propanol = 60.09 g/mole

\text{Moles of n-propanol}=\frac{1.00g}{60.09g/mole}=0.0166mole

Now we have to calculate the heat of combustion of n-propanol.

As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ

So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)

                                                                                           = 0.554 kJ/mol

Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol

5 0
3 years ago
If water evaporates can you see the solid particles of the drink mix?
zavuch27 [327]
I don't think so but I am not very good with this sort of stuff. I think it would depend on the drink mix.
8 0
3 years ago
A certain reaction has an activation energy of 51.64 kj/mol. At what temperature Kelvin will the reaction be 5.50 times faster t
pishuonlain [190]
For this, we use the Arrhenius equation to solve the problem. It is expressed as:
k = Ae^-(E/RT)

where k is the reaction rate, A is the pre-exponential factor, E is the activation energy and T is the temperature.

For a reaction, A is constant at different temperatures. We then isolate the constant and then introduce the second condition to the equation since it will still be equal to the constant. It is then simplified to:

ln(k2/k1) = -E/R (1/T2 - 1/T1)
ln(5.50k1/k1) = -51.64/8.314 (1/T2 - 1/343)
T2 = 379 K

3 0
3 years ago
How does a hypotonic solution affect a red blood cell? How does it affect a gram positive bacterial cell?
Orlov [11]

Answer:

Exposure of a red blood cell to a hypotonic solution causes swelling and eventual bursting of the cell membrane upon prolonged exposure.

Exposure of a gram positive bacterial cell causes the flow of water into the cell however, its rigid cell wall protects it from bursting.

Explanation:

A red blood cell has a cell membrane but no rigid cell wall. The inside of a red blood cell is <em>hypertonic</em> (contains more solutes like DNA, proteins) therefore, an exposure to a <em>hypotonic</em> solution ( solution with less solutes and more water), causes water to flow into the cell membrane by osmosis.

Osmosis is the movement of fluids from a region of higher concentration to a region of lower concentration. This creates a balance in fluid contents across both environments.

After prolonged exposure to the<em> hypotonic</em> solution, the flexible cell membrane swells and eventually bursts.

A gram positive bacterial cell has a rigid cell wall and a cell membrane. When exposed to a <em>hypotonic</em> solution, water flows from the outside environment to the interior of the cell by osmosis through the cell wall and membrane. The rigid cell wall of the bacterial cell however, contains the swelling and prevents the cell from bursting.

4 0
3 years ago
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