Mid- ocean ridges normally form where tectonic plates are A. converging B. diverging. C. Stationary. D. sliding past each other

Describe the relationship between the radius of a cation and that of the atom from which forms.

vichka [17]

The radius of the cation is much smaller than the corresponding neutral atom.(b) The radius of an anion is much larger than the corresponding neutral atom.Explanation:The size of the atom or ion is inversely proportional to the nuclear charge experienced by the electrons.(a)The size of the cation is smaller than the size of the corresponding neutral atom. This is because after removal of an electron from the highest principle energy level the nuclear charge experienced by the valence electrons increases resulting in the decrease in size.(b)The size of an anion is larger than the size of the corresponding neutral atom. In an anion, an extra electron is added to the highest principle energy level but the effective nuclear charge pulling the electrons towards the nucleus is still same. The net effective nuclear charge experienced by the electrons present in the outermost shell decrease. Moreover, due to the added electron, the repulsion between the electrons also increases resulting in the increase in size

Make since? i hope this helps

4 0

3 years ago

2. Matt went to his friend’s party. He ate a big meal and drank a keg of beer. He felt heartburn after the meal and took Tums to

evablogger [386]

Answer:

390.85mL

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 780 torr

Initial volume (V1) = 400mL

Initial temperature (T1) = 40°C = 40°C + 273 = 313K

Final temperature (T2) = 25°C = 25°C + 273 = 298K

Final pressure (P2) = 1 atm = 760torr

Final volume (V2) =?

Step 2:

Determination of the final volume i.e the volume of the gas outside Matt's body.

The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:

P1V1/T1 = P2V2/T2

780 x 400/313 = 760 x V2 /298

Cross multiply to express in linear form

313 x 760 x V2 = 780 x 400 x 298

Divide both side by 313 x 760

V2 = (780 x 400 x 298) /(313 x 760)

V2 = 390.85mL

Therefore, the volume of the gas outside Matt's body is 390.85mL

3 0

3 years ago

25.0 cm3 of a solution of sodium hydroxide required 18.8 cm3 of 0.0500 mol/dm3 H2SO4

marshall27 [118]

Answer:

i think so

Ba(OH)2 + H2SO4 ------> BaSO4 + 2H2O

1) Moles of Ba(OH)2 = moles of H2SO4 = 0.025L x 2)0.02M = 5.0 x 10^-4M

Concn of Ba(OH)2 in g/L = 5.0 x 10^-4M x 171.33g/mol = 0.086g/mol

7 0

3 years ago

Complete the mechanism for the reaction of 2-butanol in sulfuric acid at 140 °C by adding any missing atoms, bonds, charges, non

Svetlanka [38]

Answer:

2-Butene

Explanation:

The first step is the ionization of the acid to produce the hydronium ion. Then the OH will attack this ion to produce a charged species that can be stabilized when H2O is produced.

Then an elimination takes place to produce the more substituted alkene 2-butene and the hydronium ion is gain produced.

4 0

3 years ago

How many grams of sodium chloride decompose to yield 15 grams of chlorine gas?

defon

Answer:

24.6g of NaCl

Explanation:

Expression of the reaction:

2NaCl → 2Na + Cl₂

Given parameters:

Mass of Cl₂ = 15g

Unknown:

Mass of NaCl = ?

Solution:

To solve this problem, we have to use mole relationships.

Find the number of moles of the mass of the given specie;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of Cl₂ = 2(35.5) = 71g/mol

Number of moles = $\frac{15}{71}$ = 0.21mole

Now;

From the balanced reaction equation;

1 mole of Cl₂ is produced from 2 moles of NaCl;

0.21 mole of Cl₂ will be produced from 0.21 x 2 = 0.42mole of NaCl

So,

Mass of NaCl = number of moles x molar mass

Molar mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl = 0.42 x 58.5 = 24.6g of NaCl

8 0

3 years ago