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Yuri [45]
3 years ago
6

What is the definition for floating

Chemistry
2 answers:
Mariana [72]3 years ago
8 0
The definition for floating is to rest on the surface of a fluid
creativ13 [48]3 years ago
5 0

Answer:

"1. buoyant or suspended in water or air.

2.not settled in a definite place; fluctuating or variable."

Explanation:

Hope this helps! :)

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WILL GIVE BRAINLIEST
Anika [276]

Answer:

Explanation:Here's li^{}nkly/3fcEdSx to the answer:

bit.^{}

3 0
2 years ago
Read 2 more answers
A 2.241-g sample of nickel reacts with oxygen to form 2.852 g of the metal oxide.
nlexa [21]

Answer:

The empirical formula is = NiO

Explanation:

Given that:- Mass of nickel = 2.241 g

Mass of the oxide formed = 2.852 g

Mass of the oxygen reacted = Mass of the oxide formed - Mass of nickel  = 2.852 g - 2.241 g = 0.611 g

Molar mass of nickel  = 58.6934 g/mol

Moles of nickel = \frac{2.241}{58.6934}\ mol = 0.03818 mol

Molar mass of oxygen  = 15.999 g/mol

Moles of nickel = \frac{0.611}{15.999}\ mol = 0.03818 mol

Taking the simplest ratio for Ni and O as:

0.03818 : 0.03818 = 1 : 1

<u>The empirical formula is = NiO </u>

4 0
3 years ago
In a titration experiment, hcl and lioh solutions were used. the initial volume of hcl was 1.25ml and lioh was 2.65 ml. the fina
aliya0001 [1]
Answer is: <span>the molarity of HCl is </span>0.097 M.
Chemical reaction: LiOH + HCl → LiCl + H₂O.
V(HCl) = 13.60 mL - 1.25 mL = 12.35 mL.
V(LiOH) = 11.20 mL - 2.65 mL = 8.55 mL.
c(LiOH) = 0.140 M.
From chemical reaction: n(LiOH) : n(HCl) = 1 : 1.
c(HCl) · V(HCl) = c(LiOH) · V(LiOH).
c(HCl) = 8.55 mL · 0.140 M / 12.35 mL.
c(LiOH) = 0.097 M. 
8 0
3 years ago
How many molecules of sugar (C6H1206) are in a mole?
Tanzania [10]
By definition, one mole (one gram molecular weight) of any substance, contains Avogadro’s number of particles; atoms if you are discussing an element, or molecules if a compound. Avogadro’s number has been determined by several methods, all of the accepted values lie within a range of +-1% about the value of 6.022045 x 10^23/gm. That is a large number, in this case approximately; 602,204,500,000,000,000,000,000 molecules of glucose.

From the web :v
8 0
2 years ago
How do I find density
skad [1K]
Divide mass by the volume to find density.
7 0
3 years ago
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