Place the items in order from lowest to highest degree of internal organization

Chemistry

1 answer:

erastova [34]2 years ago

5 0

The order of internal organization from lowest to highest degree is; cell < tissue < organ < organ system

<h3>What is the order of organization?</h3>

The complexity of the parts that compose an organism lays the bedrock for the classification of life. Some organisms are composed only of one cell while others are composed of many complex systems.

The order of internal organization from lowest to highest degree is; cell < tissue < organ < organ system

Learn more about organization of life:brainly.com/question/12600270

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Missing parts:

Place the items in order from lowest to highest degree of internal organization.

1.organ system

2.tissue

3.cell

4.organ

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Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

Sonbull [250]

Answer:

Option (B) is correct

Explanation:

Oxidation: $Zn\rightarrow Zn^{2+}+2e^{-}$

Reduction: $Sn^{2+}+2e^{-}\rightarrow Sn$

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Overall: $Zn+Sn^{2+}\rightarrow Zn^{2+}+Sn$

Nernst equation for this cell reaction at $25^{0}\textrm{C}$ :

$E_{cell}=(E_{Sn^{2+}\mid Sn}^{0}-E_{Zn^{2+}\mid Zn}^{0})-\frac{0.059}{n}log\frac{[Zn^{2+}]}{[Sn^{2+}]}$

Where, n is number of electron exchanged and species inside third bracket represents concentrations in molarity.

Here, n = 2, $E_{cell}=0.660V$ and $[Zn^{2+}]=2.5\times 10^{-3}M$

So, plug in all the given values into above equation:

$0.660V=(-0.136V+0.76V)-\frac{0.059}{2}log\frac{2.5\times 10^{-3}M}{[Sn^{2+}]}$

So, $[Sn^{2+}]=4.2\times 10^{-2}M$

As the value "0.059" varies from literature to literature and $4.2\times 10^{-2}M$ is most closest to $3.3\times 10^{-2}M$ therefore option (B) is correct.