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balandron [24]
2 years ago
9

Place the items in order from lowest to highest degree of internal organization

Chemistry
1 answer:
erastova [34]2 years ago
5 0

The order of internal organization from lowest to highest degree is; cell <  tissue < organ < organ system

<h3>What is the order of organization?</h3>

The complexity of the parts that compose an organism lays the bedrock for the classification of life. Some organisms are composed only of one cell while others are composed of many complex systems.

The order of internal organization from lowest to highest degree is; cell <  tissue < organ < organ system

Learn more about organization of life:brainly.com/question/12600270

#SPJ1

Missing parts:

Place the items in order from lowest to highest degree of internal organization.

1.organ system

2.tissue

3.cell

4.organ

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Sometimes in lab we collect the gas formed by a chemical reaction over water (see sketch at right). This makes it easy to isolat
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Answer:

The correct answer is 0.12 grams.

Explanation:

The mass of carbon monoxide or CO collected in the tube can be determined by using the ideal gas equation, that is, PV = nRT.

Based on the given question, P or the pressure of the gas is given as 1 atm, volume of the gas collected in the tube is 117 ml or 0.117 L.  

The number of moles or n can be determined by using the equation, mass/molar mass.  

R is the universal gas constant, whose value is 0.0821 L atmK^-1mol^-1, and temperature is 55 degree C or 328 K (55+273).  

On putting the values we get:

n = PV/RT

= (1 atm*0.117 L) / (0.0821 L atmK^-1mol^-1 * 328 K)

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3 years ago
A 1.68 g sample of water is injected into a closed evacuated 5.3 liter flask at 65°C. What percent (by mass) of the water will b
Angelina_Jolie [31]

Answer:

50.4 % of the water will be vapor

Explanation:

<u>Step 1:</u> Data given

Mass of water = 1.68 grams

volume of the flask = 5.3 L

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<u>Step 2:</u> Calculate moles of H2O

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⇒ p = the pressure of water = 0.2467 atm

⇒ V = the volume of the flask = 5.3 L

⇒ n = moles of water

⇒ R = gas constant = 0.08206 L*atm/ K*mol

⇒ T = the temperature = 65°C = 338 Kelvin

n = (p*V)/(R*T)

n = (0.2467 * 5.3) /(0.08206* 338)

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Mass of water = moles of water * molar mass of water

Mass of water = 0.047 moles *18.02 g/mol

Mass of water = 0.84694 grams

<u>Step 4:</u> Calculate the percent of water vaporized

% = (0.84694 grams/1.68 grams) *100%

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50.4 % of the water will be vapor

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