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3 years ago

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Which of the following is an example of an abiotic factor? A wind factor B Human C bacterium D duck

2 answers:

solmaris [256]3 years ago

7 0

Abiotic factors, also called abiotic components, are non-living parts of the environment which affects the living organisms and their function in the ecosystem. I think the correct answer is A. Wind factor is the only non-living part from the choices.

marysya [2.9K]3 years ago

5 0

I think it's A hope it helps

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Identify the element in C6H12O6 that allows it to be classified as an organic compound.

Alja [10]

Answer:

Carbon (C)

Explanation:

Organic chemistry is generally defined as the chemistry of carbon compounds. In order words, organic compounds are those compounds that contain carbon.

However, one characteristic of organic compounds is that in organic compounds, carbon links to itself to form long chains. This property is known as catenation. When we look at the compound. There are six carbon to carbon linkages. This is typical of organic compounds. Hence the substance is an organic compound.

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4 years ago

Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and

Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

The given data is as follows.

mass = 500 g, $C_{p}$ = 24.4 J/mol K

$T_{h}$ = 500 K, $T_{c}$ = 250 K

Mass number of copper = 63.54 g /mol

Number of moles = $\frac{mass}{/text{\molar mass}}$

= $\frac{500}{63.54}$

= 7.86 moles

Now, equating the entropy change for both the substances as follows.

$7.86 \times 24.4 \times [T_{f} - 250]$ = $7.86 \times 24.4 \times [500 -T_{f}]$

$T_{f} - 250 = 500 - T_{f}$

$2T_{f}$ = 750

So, $T_{f}$ = $375^{o}C$

For the metal block A, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{500}]$

= -3.04 J/ K mol

For the block B, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{250}]$

= 4.296 J/Kmol

And, total entropy change will be as follows.

= 4.296 + (-3.04)

= 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.

8 0

3 years ago

who tryna do this https://app.senecalearning.com/classroom/course/ce229c78-825a-4e3f-a348-e79401f6a225/section/d2802d1d-741a-43f

Dahasolnce [82]

Answer:ME

Explanation:

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3 years ago

What is plate tectonics?

Alexandra [31]

Plate tectonics is the theory that Earth's crust is composed of many plates that are moving slowly over time.

Your answer is D. :)

7 0

4 years ago

Read 2 more answers

What is the net ionic equation of the reaction of FeCl2 with NaOH? Express you answer as a chemical equation including phases.

Lilit [14]

Answer:

Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s)

Explanation:

To determine the reaction, we define the reactants:

FeCl₂, NaOH

We dissociate them:

FeCl₂(aq) → Fe²⁺(aq) + 2Cl⁻ (aq)

NaOH (aq) → Na⁺ (aq) + OH⁻(aq)

Salts from chloride are soluble, except for Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

The OH⁻ and the Fe²⁺ bonds to make a precipitate.

So, the molecular complete equation is:

FeCl₂(aq) + 2NaOH(aq) → Fe(OH)₂(s) ↓ + 2NaCl(aq)

When we dissociate the elements, we get the net ionic equation but as we produced an state's change, the compound stays the same.

We cancel the spectators ions (the ones, that are repeated)

Fe²⁺(aq) + 2Cl⁻ (aq) + 2Na⁺ (aq) + 2OH⁻(aq) → Fe(OH)₂(s) + 2Na⁺(aq) + 2Cl⁻(aq)

Fe²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s)

5 0

3 years ago