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Harrizon [31]
3 years ago
7

C2H4(g) + H2(g) mc030-1.jpg C2H6(g) Which change would likely cause the greatest increase in the rate of the reaction?

Chemistry
2 answers:
amm18123 years ago
8 0
<h3><u>Answer;</u></h3>

increasing temperature and pressure

<h3><u>Explanation;</u></h3>
  • The reaction involves gases;

<em>C2H4(g) + H2(g) → C2H6(g)</em>

  • Therefore, <em><u>a change in pressure and temperature greatly affects the rate of reaction or the rate at which the products are formed.</u></em>
  • <em><u>Increasing the pressure in the reaction favors the rate of reaction</u></em> as the 2 volumes of the reactants forms 1 volume of the product and thus compression is evident, which will increase the rate of reaction.
  • <em><u>Increasing the temperature also increases the rate of reaction due to increases in the kinetic energy of molecules of the reactants and thus an increase in the number of collision by the particles of the reactants </u></em>and thus the speed at which the products are formed.
Vinil7 [7]3 years ago
5 0
The reaction is a hydrogenation reaction of an alkene, and its equation is:
C₂H₄(g) + H₂(g) → C₂H₆(g)
Therefore, this reaction can be sped up just as any other irreversible reaction may have its rate increased, by increasing temperature and pressure to increase the effective collisions of molecules.
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Waves with higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths
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The sun is a mid-sized, main sequence star. What stage is next in the life cycle of the sun?
ss7ja [257]

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It starts to become a red giant!

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7 0
3 years ago
One mole of an ideal gas is contained in a cylinder with a movable piston. The temperature is constant at 77°C. Weights are remo
frozen [14]

Answer:

The total work is 4957.45J

Explanation:

For an ideal gas, at constant temperature the definition of work (W) is

W = - P.dV = - n.R.T \int\limits^i_f {\frac{dV}{V} \\W = - n.R.T. Ln (\frac{V_{f}}{V_{I}})\\W = - n.R.T. Ln (\frac{P_{i}}{P_{f}})

where P is the pressure, V the volume, n the moles number, T the temperature and R the gas constant.

To solve the problem is necessary to replace the two steps in the equation

Stape 1: n  = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 5.50atm and Pf = 2.43atm.

W_{1} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{5.50atm}{2.43atm}) = 23.44atm.Lx101.325\frac{J}{atm.L} =2375.44J

Stape 2: n  = 1 mol, R = 0.082atm.L/K.mol, T = 77ºC = 350K, Pi = 2.43atm and Pf = 1.00atm.

W_{2} = - 1molx0.082\frac{atm.L}{K.mol}x350KxLn (\frac{2.43atm}{1.00atm}) = 25.48atm.Lx101.325\frac{J}{atm.L} =2582.01J

The total work is the sum of the two steps

W = W_{1} + W_{2} = 2375.44J + 2582.01J = 4957.45J

4 0
3 years ago
In the Lewis structure of the iodate ion, IO3 – , that satisfies the octet rule, the formal charge on the central iodine atom is
vitfil [10]

Answer:

- 1 is the correct option

Explanation:

In determining the oxidation state or formal charge on element in an ionic specie, the whole ion need to be equated to the value of charge on the ion.

For example in this case, the charge on the ion is -3. Thus; representing iodine with X and putting -2 for the oxidation state of O (oxygen)

X + -2 = -3 (adding 2 to both side)

X = -3 + 2

X = - 1

6 0
3 years ago
Question 18 (5 points)
NeX [460]

Answer:

d. oxygen is a pure substance and rocks are mixtures

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