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Harrizon [31]
3 years ago
7

C2H4(g) + H2(g) mc030-1.jpg C2H6(g) Which change would likely cause the greatest increase in the rate of the reaction?

Chemistry
2 answers:
amm18123 years ago
8 0
<h3><u>Answer;</u></h3>

increasing temperature and pressure

<h3><u>Explanation;</u></h3>
  • The reaction involves gases;

<em>C2H4(g) + H2(g) → C2H6(g)</em>

  • Therefore, <em><u>a change in pressure and temperature greatly affects the rate of reaction or the rate at which the products are formed.</u></em>
  • <em><u>Increasing the pressure in the reaction favors the rate of reaction</u></em> as the 2 volumes of the reactants forms 1 volume of the product and thus compression is evident, which will increase the rate of reaction.
  • <em><u>Increasing the temperature also increases the rate of reaction due to increases in the kinetic energy of molecules of the reactants and thus an increase in the number of collision by the particles of the reactants </u></em>and thus the speed at which the products are formed.
Vinil7 [7]3 years ago
5 0
The reaction is a hydrogenation reaction of an alkene, and its equation is:
C₂H₄(g) + H₂(g) → C₂H₆(g)
Therefore, this reaction can be sped up just as any other irreversible reaction may have its rate increased, by increasing temperature and pressure to increase the effective collisions of molecules.
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Fast, Direction, Time

Explanation:

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3 years ago
How many grams of O are in 675 g of Na2O
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A certain amount of hydrogen peroxide was dissolved in 100. mL of water and then titrated with 1.68 M KMnO4. What mass of H2O2 w
Stels [109]

Answer:

see explanation below

Explanation:

First to all, this is a redox reaction, and the reaction taking place is the following:

2KMnO4 + 3H2SO4 + 5H2O2 -----> 2MnSO4 + K2SO4 + 8H2O + 5O2

According to this reaction, we can see that the mole ratio between the peroxide and the permangante is 5:2. Therefore, if the titration required 21.3 mL to reach the equivalence point, then, the moles would be:

MhVh = MpVp

h would be the hydrogen peroxide, and p the permanganate.

But like it was stated before, the mole ratio is 5:2 so:

5MhVh = 2MpVp

Replacing moles:

5nh = 2MpVp

Now, we just have to replace the given data:

nh = 2MpVp/5

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Now to get the mass, we just need the molecular mass of the peroxide:

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8 0
3 years ago
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7 0
3 years ago
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enyata [817]

Answer:

It's <em>True</em> very true darling

4 0
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