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3 years ago

Convert $25 in dimes (I need explanation as well)

Physics

1 answer:

CaHeK987 [17]3 years ago

7 0

Answer: To convert this into dimes it's basically like 25 divided by 10.

25 / 10 = 2.5, So you'd need two dimes and a nickel.

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A 430 g soccer ball lying on the ground is kicked and flies off at 25 m/s. If the duration of the impact was .01 s, what was the

maw [93]

<h2>The average force acting on the ball is 1075 N in the direction of travel of ball.</h2>

Explanation:

Force is given by rate of change of momentum.

Mass of soccer ball = 430 g = 0.43 kg

Initial velocity = 0 m/s

Final velocity = 25 m/s

Change in momentum = 0.43 x 25 - 0.43 x 0

Change in momentum = 10.75 kg m/s

Time taken = 0.01 s

Rate of change of momentum = Change in momentum ÷ Time

Rate of change of momentum = 10.75 ÷ 0.01

Rate of change of momentum = 1075 N

Force = 1075 N

The average force acting on the ball is 1075 N in the direction of travel of ball.

4 0

3 years ago

Calculate The pressure produced by a force of 392 N acting on an area of 8.0 m^2

Nonamiya [84]

Answer:

Explanation:

500-0.05=499.95

500-100+5=405

100+100=10000

5 0

2 years ago

Why metal wire coated with plastic or rubber is used in electric circuits

kolezko [41]

Because plastic and rubber are known as insulators which keep metal wires protected

7 0

3 years ago

A fixed coil of wire with 10 turns and an area of 0.055 m2 is placed in a perpendicular magnetic field. This field oscillates in

Blababa [14]

Answer:

Part a)

Average EMF for half cycle is

$E_{avg} = 2.64 V$

Part b)

For one complete cycle we will have

$E_{avg} = 0$

Part c)

Maximum induced EMF will be at

t = 0.025 s and 0.075 s

minimum induced EMF is at

t = 0.05s and 0.1 s

Explanation:

As we know that magnetic field is oscillating in direction as well as magnitude

so induced EMF is given as

$E = NBA\omega sin(\omega t)$

Part a)

For average value of EMF from positive maximum to negative maximum which is equal to half cycle

so we have

$E_{avg} = NBA\omega \frac{2}{T}\int_0^{T/2} sin(\omega t) dt$

$E_{avg} = \frac{2NBA\omega}{\pi}$

$E_{avg} = \frac{2(10)(0.12)(0.055)(2\pi (10))}{\pi}$

$E_{avg} = 2.64 V$

Part b)

For one complete cycle we will have

$E_{avg} = NBA\omega \frac{1}{T}\int_0^T sin(\omega t) dt$

$E_{avg} = 0$

Part c)

Maximum induced EMF will be at

$t = \frac{T}{4} and \frac{3T}{4}$

here we know

$T = \frac{1}{f} = 0.1 s$

t = 0.025 s and 0.075 s

minimum induced EMF is at

$t = \frac{T}{2} and T$

so it is

t = 0.05s and 0.1 s

8 0

4 years ago

A star with a mass like the Sun which will soon die is observed to be surrounded by a large amount of dust and gas -- all materi

Dafna11 [192]

Answer: D. Infrared

Infrared is the best way to observe it.

5 0

3 years ago