Answer:
The right statement is "The percent transmittance of light, %T, will be higher for Sample 1 compared to Sample 2."
Explanation:
The Beer-Lambert Law states that the absorbance is directly proportional to the concentration of the substance.
Absorbance = εLc
ε: molar absorptivity coeficient
L: optical path length
c: molar concentration
Therefore, if ε and L are the same, the higher the concentration, the higher the absorbance and the lower the transmitance.
Since sample 1 has a higher concentration of CuSO₄ than sample 2, sample 1 has a higher absorbance and lower percent transmittance.
Explanation:
A stable isotope is one that does not emit radiation, or, if it does its half-life is too long to have been measured. It is believed that the stability of the nucleus of an isotope is determined by the ratio of neutrons to protons.
Hope this helps you out : D
It will lose them and become stable
Answer:
Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state
Answer:
See Explanation
Explanation:
Given that;
N/No = (1/2)^t/t1/2
Where;
No = amount of radioactive isotope originally present
N = A mount of radioactive isotope present at time t
t = time taken
t1/2 = half life
N/1000=(1/2)^3/6
N/1000=(1/2)^0.5
N = (1/2)^0.5 * 1000
N= 707 unstable nuclei
Since the value of the initial activity of the radioactive material was not given, the activity of the radioactive material after three months is given by;
Decay constant = 0.693/t1/2 = 0.693/6 months = 0.1155 month^-1
Hence;
A=Aoe^-kt
Where;
A = Activity after a time t
Ao = initial activity
k = decay constant
t = time taken
A = Aoe^-3 *0.1155
A=Aoe^-0.3465
