The moles of water that are produced from 373 moles of ammonia present in any chemical reaction is 746 moles.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the amount of entities present in any chemical reaction before and after the reaction.
Given chemical reaction is:
3Al + 3NH₄ClO₄ → Al₂O₃ + AlCl₃ + 3NO + 6H₂O
From the stoichiometry of the reaction it is clear that:
3 moles of Al = produces 6 moles of H₂O
373 moles of Al = produces 6/3×373 = 746 moles of H₂O
Hence required moles of water is 746 moles.
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brainly.com/question/21931988
<span>Balanced chemial equation:
2NaI(aq)+Hg2(NO3)2(aq) →Hg2 I2 (s) + 2 NaNO3 (aq)
You can see it better if I use latex:

As per the phases this is the interpretation:
The symbols (aq) stands for aquous meaning that the compound is dissolved in water.
The symbol (s) stands for solid, meaning tha the compound precipitate and is not dissolved in water.</span><span>
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Answer:
E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)
Explanation:
Which ONE of the following is an oxidation–reduction reaction?
A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.
B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.
C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.
D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.
E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. <u>C is reduced</u> and <u>H is oxidized</u>.