After the ball leaves the thrower's hand, the only force on it is
due to gravity. There's no horizontal force acting on it at all. (C)
Answer:
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
Explanation:
According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential (
) and radial accelerations (
), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration (
), measured in meters per square second, is:
(Eq. 1)
Magnitudes of tangential and radial accelerations are determined by using the following formulas:
(Eq. 1)
(Eq. 2)
Where:
, 
- Initial and final speeds, measured in meters per second.
- Time, measured in seconds.
- Radius, measured in meters.
If we know that 
, 
, 
and 
, then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
(a) the principle of aerodynamic convergence
(b) the centripetal force
(c) Conservation of angular momentum
(d) Conservation of kinetic energy
(e) None of these
Conservation of angular momentum
Answer: Option C.
<u>Explanation:</u>
The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.
The law of conservation of angular momentum expresses that the angular energy of a body that is the result of its snapshot of latency about the hub of revolution and its rakish speed about a similar pivot, can't change except if an outside torque follows up on the framework.
<span>e=ca{\displaystyle e={\frac {c}{a}}}.</span>
