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Irina-Kira [14]
2 years ago
5

A particle has an acceleration of +6.24 m/s2 for 0.300 s. At the end of this time the particle's velocity is +9.81 m/s. What was

the particle's initial velocity?
Physics
2 answers:
Lady_Fox [76]2 years ago
8 0
The formula we will be using is:

Final Velocity = Initial Velocity + Acceleration * Time
v = u + at
u = v - at = 9.81 - 6.24*0.3 = 7.938 m/s
aivan3 [116]2 years ago
8 0

Answer:

v_0=7.938\frac{m}{s}

Explanation:

This is uniformly accelerated motion, that is to say a motion with constant acceleration, we can use the kinematic equations, especifically the which one that relate the change in speed to acceleration and time:

v_f-v_0=at

So, Rewriting for initial speed:

v_0=v_f-at\\v_0=9.81\frac{m}{s}-(6.24\frac{m}{s^2})0.3s\\v_0=9.81\frac{m}{s}-1.872\frac{m}{s}\\v_0=7.938\frac{m}{s}

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Read 2 more answers
The bellow of a territorial bull hippopotamus is measured at 100 dB above the threshold of hearing. What is the sound intensity?
Dmitriy789 [7]

Answer:

Explanation:

The hippopotamus hearing threshold is 100dB

β = 100 dB

The threshold of human hearing is Io = 1 × 10^-12 W/m²

The sound intensity level is given as

β = 10•Log(I / Io)

100 = 10•Log(I / Io)

Divided Both sides by 10

100 / 10 = Log(I / Io)

10 = Log(I / Io)

Take inverse Logarithm ( antilog) of both sides

10^10 = 10^[Log(I / Io)]

10^10 = I / Io

Then,

I = 10^10 × Io

I = 10^10 × 1 × 10^-12

I = 1 × 10^-2 W/m²

I = 0.01 W/m²

The sound intensity is 0.01 W/m²

5 0
2 years ago
The sound intensity at a distance 2.00 m from a sound source is 5.00 Find the total sound energy emitted by the source in each s
notka56 [123]

Answer:

     P = 251, 3 W

Explanation:

The intensity is defined as the power emitted per unit area

           I = P / A

Since sound is distributed in all directions spherical shape, the area of ​​a sphere is

           A = 4π r²

let's clear the power and replace

         P = I A

         P = I (4π r²)

let's calculate

         P = 5.00 (4π 2²)

         P = 251, 3 W

6 0
3 years ago
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