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Irina-Kira [14]
3 years ago
5

A particle has an acceleration of +6.24 m/s2 for 0.300 s. At the end of this time the particle's velocity is +9.81 m/s. What was

the particle's initial velocity?
Physics
2 answers:
Lady_Fox [76]3 years ago
8 0
The formula we will be using is:

Final Velocity = Initial Velocity + Acceleration * Time
v = u + at
u = v - at = 9.81 - 6.24*0.3 = 7.938 m/s
aivan3 [116]3 years ago
8 0

Answer:

v_0=7.938\frac{m}{s}

Explanation:

This is uniformly accelerated motion, that is to say a motion with constant acceleration, we can use the kinematic equations, especifically the which one that relate the change in speed to acceleration and time:

v_f-v_0=at

So, Rewriting for initial speed:

v_0=v_f-at\\v_0=9.81\frac{m}{s}-(6.24\frac{m}{s^2})0.3s\\v_0=9.81\frac{m}{s}-1.872\frac{m}{s}\\v_0=7.938\frac{m}{s}

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Answer:

Explanation:

(a)

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Volume of atmosphere = volume of (earth +atm osphere) — volume of earth

= \frac{4}{3}\pi(6400+ 50)^3 -  \frac{4}{3}\pi (6400)
^3\\\\=  \frac{4}{3}\pi(6192125000) km’^3\\= 2.6\times 10^{19} m^3

Hence the volume of atmosphere is 2.6\times 10^{19} m^3

(b)

Write the ideal gas equation as foll ows:

PV = nRT\\\\n\frac{0.20atm\times 2.6\times10^{19} m^3}{0.08206L\, atm/mok\, K \times (15+273+15)K}\times \frac{1L}{10^{-3}m^3}\\\\= 2.20\times 10^{20} moles

no.\, of\, molecules = 2.20\times 10^{20} moles \times \frac{6.022\times10^{23}\,molecules}{1mole}= 13.3\times10^{43} molecules


Hence the required molecules is 13.3\times10^{43} molecules


(c)

Write the ideal gas equation as follows:

PV =nRT
\\\\n=\frac{1.0 atm \times 0.5L
}{0.08206 L\, atm/mol\,K \times (37 +273.1 5)K} = 0.0196 moles

no.\, of\, molecules = 0.0196 moles \times\frac{6.022\times10^{23} molecules}
{Imole}= 1.2\times 10^{23} molecules

Hence the required molecules in Caesar breath is 1.2\times 10^{23} molecules

(d)

Volume fraction in Caesar last breath is as follows:  

Fraction,\, X =\frac{12\times 10 molecules}{13.3\times 10^{43} \,molecules}= 9.0\times 10\, molecule/air\, molecule}

(e)

Since the volume capacity of the human body is 500 mL.

Volume\, of\, Caesar\, nreath\, inhale\, is =\frac{ 12\times 10^{22}\, molecules}{breath}\times \frac{9.0\times10^{-23} molecule}{air\, molecule}\\\\= 1.08 molecule/breath

5 0
3 years ago
Which material is LEAST dense?<br> zircon<br> oxygen<br> carbon disulfide<br> air
Natalija [7]

Answer:

Carbon disulfide soryy if im wrong\

Explanation:

7 0
3 years ago
We define the specific heat of a material as the energy that must be transferred to 1.0 kg of that material in order to cause it
Nezavi [6.7K]

Answer:

No change in the specific heat.

Explanation:

Specific heat is an intrinsic property that it has not depend upon on the amount of substance or energy added, it depends upon the material.

So, when twice the amount of energy is transferred, specific heat of the material does not change rather the energy that is twice in the amount to 1 kg of that material cause it to warm 2.0° C.

8 0
3 years ago
A 8.3-g wad of sticky clay is hurled horizontally at a 82-g wooden block initially at rest on a horizontal surface. The clay sti
Bingel [31]

Answer:

The speed of the clay before the impact was 106.35 m/s.

Explanation:

the only force doing work on the system is the frictional force, f, the work done by f is given by:

Wf = ΔK = Kf - Ki

The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:

         f×Δx = Ki

m×g×Δx×μ = 1/2×m×v^2

           v^2 = 2×g×Δx×μ

                  =  2×(9.8)×(7.50)×(0.650)

                  = 95.55

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This is the veloty of clay and block after the clay hit the block.

if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:

m×v1 +M×V = v(m + M)

         m×v1 = v(m + M)

              v1 = v(m + M)/m

              v1 =  (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)

              v1 =  106.35 m/s

Therefore, the speed of the clay before the impact was 106.35 m/s.

3 0
3 years ago
30. A generation is about one-third of a lifetime. Approximately how many generations have passed since the year 0 AD?
Ierofanga [76]

Answer:84 generations

Explanation:

A generation is about one-third of a lifetime. Approximately how many generations have passed since the year 0 AD? Approximately 84 generation.

5 0
3 years ago
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