The work that a force does by acting on an object is equal to what?

A ball is thrown horizontally from a platform so that the initial height of the ball is 6.0 m above the level ground below. The

solniwko [45]

We can first obtain time of flight from vertical fall
Initial velocity U=0, d = 6 m, a = 9.8 m/s²
d = ut + 1/2 at²
6.0 = 0 + (1/2 × 9.80 t²)
t = √(12/9.8)
= 1.106 sec
Horizontal velocity = Vh = Dh/t
= 24.0 /1.106 s
= 21.69 m/s
The ball was thrown at a speed of 21.69 m/s

5 0

4 years ago

PLS ANSWER ASAP

poizon [28]

Answer:

Gravity, normal force, friction, and air resistance.

Explanation:

Assuming the ball is on earth, there is always gravity acted upon the object.

Since the problem said that the golf ball is moving throughout the air, we can tell that there will be air resistance and friction(air resistance is a type of friction). There is also normal force pushing on the ball as it bumps into the air, as the air is pushing back with an equal and opposite force.

I don't know what you mean by "applied", so I don't think there's that type of force exerted on the ball.

Lastly, tension only occurs when you pull a string/rope. There is no string/rope in this case, so there is no tension exerted on the ball.

I hope this helped you.

8 0

3 years ago

When an object such as a plastic comb is charged by rubbing it with a cloth, the net charge is typically a few microcoulombs. If

masya89 [10]

The concept required to solve this problem is quantization of charge.

First the number of electrons will be calculated and then the total mass of the charge.

With these data it will be possible to calculate the percentage of load in the mass.

$Q= ne$

Here Q is the charge, n is the number of electrons and e is the charge on the electron

$n = \frac{Q}{e}$

Replacing,

$n = \frac{4*10^{-6}C}{1.6*10^{-19}}$

$n = 2.5 * 10^{13}77$

According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron

The total mass of the charge is

$m= nm_e$

Here,

m = Mass of the charge

n = Number of electrons

$m_e$ = Mass of the electron

$\text{Percentage change} = \frac{nm_e}{M}*100$

Replacing we have

$\text{Percentage change} = \frac{(2.5*10^13)(9.1*10^{-28})}{33}*100$

$\text{Percentage change} = 6.9*10^{-14} \%$

6 0

4 years ago

As a solid reaches its melting point intermolecular bonds have been disrupted, causing:

yarga [219]

Answer:

Explanation: B. A change in particle position

4 0

4 years ago

Read 2 more answers

A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8

Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

$\eta =1-\frac{T_c}{T_h}$