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Molar mass of Al₂(CrO₄)₃ is the mass of one mole of Al₂(CrO₄)₃
one mol =weight of Al₂(CrO₄)₃ in g /one mol
1) We have to find the atomic mass (in a periodic talbe) of the following elements (in u)
Al=26.98 u
Cr=52 u
O=16 u
2)We calculate the atomic weight of Al₂(CrO₄)₃
Atomic weight (Al₂(CrO₄)₃)=2(26.98 u)+3[(52 u)+4(16 u)]=
=53.96 u+3(52 u+64 u)=53.96 u+3(116 u=53.96 u+348 u=401.96 u
3) One mole of (Al₂(CrO₄)₃ ) have 401.96 g of Al₂(CrO₄)₃
molar mass=401.96 g/ mol
answer: 401.96 g/ mol
Answer: Option (d) is the correct answer.
Explanation:
A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.
(a)
Will be written as:

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(b) 
Will be written as:

Similarly here, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(c) 
Will be written as:

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.
(d) 
So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.
Thus, we can conclude that
is an oxidation-reduction reaction.
The key results explain how you'll achieve a certain goal. They have to be quantitative, but always measurable in terms of their progress. This has to be considered when it comes to key results, because only results count for each milestone on the way to achieving the goal in question.