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3 years ago

If 5.0 moles of water are decomposed how many moles of oxgyen are formed

Chemistry

1 answer:

JulijaS [17]3 years ago

4 0

Answer:

5 moles of H2

Explanation:

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HELPPP! How is a gas different from a solid or a liquid?

Korolek [52]

A gas has more free molecules, and it is air, not a tangible substance. Hope it helps! :)

6 0

3 years ago

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The half-life of argon-39 is 269 years. It decays into krypton-39. After 1,076 years, what fraction of the original amount of ar

Darya [45]

Answer:

1/16

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 269 years

Time (t) = 1076 years

Fraction remaining =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 269 years

Time (t) = 1076 years

Number of half-lives (n) =?

n = t / t½

n = 1076 / 269

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the fraction of the original amount remaining. This can be obtained as follow:

Let N₀ be the original amount.

Let N be the amount remaining.

Number of half-lives (n) = 4

Fraction remaining (N/N₀ ) =?

N = 1/2ⁿ × N₀

N = 1/2⁴ × N₀

N = 1/16 × N₀

Divide both side by N₀

N/N₀ = 1/16

Thus, the fraction of the original amount remaining is 1/16

8 0

3 years ago

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What is the molarity of NaOH if 83.5 mL of NaOH is needed to react with 35.0mL of a 0.275 M solution of H2SO4?

Lostsunrise [7]

Answer:

0.231 mol/L

Explanation:

The first step is to write the balanced equation for this reaction:

$H_{2}SO_{4} +2NaOH ===> Na_{2}SO_{4} +2H_{2}O$

The second step is to find the number of moles in the acid:

number of moles = volume * concentration

= 0.035 L * 0.275 mol/L

= 0.009625 mol

The third step is to use the molar ratio from the balanced chemical equation to find the number of moles of NaOH that can neutralize 0.009625 mol of sulphuric acid.

n(sulphuric acid) : n(sodium hydroxide)

1 : 2

0.009625 mol : x

x = 0.01925 mol

Fourth step is to calculate the concentration of sodium hydroxide:

$concentration = \frac{number of moles}{volume} = \frac{0.01925}{0.0835} =0.231 mol/L$

7 0

3 years ago

Which sample contains a total of 6.0 x 1023 molecules? Select one: a. 4.0 g of He b. 14 g of Li c. 80 g of Br2 d. 4.0 g of H2

navik [9.2K]

Answer:

Option a. 4 g of He

Explanation:

6.02×10²³ is the Avogadro's number. The amount of units that corresponds to 1 mol, in this case the units are molecules.

Let's find out which mass corresponds to 1 mol (mass / molar mass)

a. 4g / 4g/mol = 1 mol He

b. 14g / 6.94 g/mol = 2.01 mol Li

c. 80g /159.8 g/mol = 0.5 moles Br₂

d. 4g / 2g/mol = 2 mol H₂

3 0

3 years ago

The mass ratio of H to O in water (H2O) is 1:8. What is the mass

svp [43]

Answer: 1:16

Explanation:

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3 years ago