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vampirchik [111]
3 years ago
13

Two unknown compounds are tested. Compound 1 contains 15.0g of hydrogen and 120.0g of oxygen. Compound 2 contains 2.0g of hydrog

en and 32.0g of oxygen. Are the compounds the same? Explain your answer.
Chemistry
1 answer:
ivann1987 [24]3 years ago
7 0

Answer:

The both compounds are different.

Explanation:

In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.

Given data:

For compound 1.

Mass of hydrogen = 15 g

Mass of oxygen = 120 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol

Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol

Total number of moles = 22.5 mol

% of hydrogen = 15 /22.5 × 100 = 66.7%

% of oxygen = 7.5 / 22.5× 100 = 33.3%

For compound 2:

Mass of hydrogen = 2 g

Mass of oxygen = 32 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol

Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol

Total number of moles = 4 mol

% of hydrogen = 2 /4 × 100 = 50%

% of oxygen = 2 / 4× 100 = 50%

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3 0
1 year ago
Why does a reaction slow down with time?
MrMuchimi

Answer:

first mark me  Brainliest

Explanation:

Reaction rate, in chemistry, the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time. Alternatively, it may be defined in terms of the amounts of the reactants consumed or products formed in a unit of time. For example, suppose that the balanced chemical equation for a reaction is of the form

A + 3B → 2Z.

4 0
3 years ago
Read 2 more answers
What is the lewis structure and formal charge of CH2O
aksik [14]

Diagram A shows the Lewis structure (LS) of CH_2O. The formal charge on each atom is zero.

To get the formal charge (FC) on the atoms, cut each bond in half, as in <em>Diagram B</em>.  Each atom gets the electrons on its side of the cut.

Formal charge = valence electrons in isolated atom - electrons on bonded atom

FC = VE - BE  

<em>On O: </em>

VE = 6

BE = 2 lone pairs 2 + 2 bonding electrons = 4 + 2 = 6

FC = 6 – 6 = 0.

<em>On H: </em>

VE = 1

BE = 1 bonding electron

FC = 1 – 1 = 0

<em>On C: </em>

VE = 4

BE = 1 in each single bond + 2 in the double bond = 2 + 2 = 4

FC = 4 - 4 = 0

3 0
3 years ago
Rasheed calculates that his chemical reaction should produce 4 moles of product, but when he does the experiment, he gets only 3
Brut [27]

Answer:

The answer to your question is 75%

Explanation:

Data

Theoretical production = 4 moles

Experimental production = 3 moles

Percent yield = ?

Formula

Percent yield = \frac{Experimental production}{Theoretical production} x 100

Substitution

Percent yield = \frac{3}{4} x 100

Result

Percent yield = 75 %

8 0
3 years ago
In a coffee-cup calorimeter, 100.0 g of H2O and 100.0 mL of 1M HCl are mixed. The HCl had an initial temperature of 44.6 C and t
Hatshy [7]

Answer:

Exothermic reaction for the HCl, endothermic reaction for the water

2803.28\ \text{J}

Explanation:

Heat was lost by HCl as its temperature lowered, so it was an exothermic reaction for the HCL.

Heat was gained by water as its temperature increased, so it was an endothermic reaction for the water.

m = Mass of water = 100 g

c = Specific heat of water = 4184\ \text{J/kg}^{\circ}\text{C}

\Delta T = Change in temperature of water = (31.3-24.6)^{\circ}\text{C}

Heat is given by

Q=mc\Delta T\\ =0.1\times 4184\times (31.3-24.6)\\ =2803.28\ \text{J}

Heat gained by water is 2803.28\ \text{J}.

5 0
3 years ago
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