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musickatia [10]
3 years ago
12

PLEASE HELP ME !!!!!!!

Chemistry
1 answer:
love history [14]3 years ago
5 0

Answer:

it would be 5,045

Explanation:

because it is closer to 5,000. pls correct me if wrong

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hich of the following statements is not true for an exothermic reaction? Question 2 options: The products have a higher heat con
yKpoI14uk [10]

Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings.

3 0
3 years ago
What is the attraction between molecules within a substance called? adhesion capillary action cohesion polarity.
cestrela7 [59]

Answer:

cohesion

Explanation:

just got it right

5 0
2 years ago
Read 2 more answers
A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. Calculate the pressure when the volume is 1.41 L and the
Vlad1618 [11]

A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

<h3>What is Combined Gas Law ?</h3>

This law combined the three gas laws that is (i) Charle's Law (ii) Gay-Lussac's Law and (iii) Boyle's law.

It is expressed as

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where,

P₁ = first pressure

P₂ = second pressure

V₁ = first volume

V₂ = second volume

T₁ = first temperature

T₂ = second temperature

Now put the values in above expression we get

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

\frac{1.02\ atm \times 2.30\ L}{281\ K} = \frac{P_2 \times 1.41\ L}{298\ K}

P_{2} = \frac{1.02\ atm \times 2.30\ L \times 298\ K}{281\ K \times 1.41\ L}

P₂ = 1.76 atm

Thus from the above conclusion we can say that A sample of an ideal gas has a volume of 2.30 L at 281 K and 1.02 atm. 1.76 atm is the pressure when the volume is 1.41 L and the temperature is 298 K.

Learn more about the Combined gas Law here: brainly.com/question/13538773

#SPJ4

4 0
2 years ago
2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??
Zepler [3.9K]

Answer:

d=1.78\times 10^{-7}\ Dg/\mu m^3

Explanation:

Given,

The density of Helium is 1.78\times 10^4\ g/cm^3

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3

So, the density of Helium is equal to 1.78\times 10^{-7}\ Dg/\mu m^3.

4 0
3 years ago
A piece of copper has a volume 130 L. What is the mass of the sample, in units of kilograms?
Reil [10]

Answer: The mass of the sample is 1264.800 kg.

Explanation:

Mass of the piece of copper = m

Volume of the copper price = 130 L=130,000 cm^3

1 L= 1,000 cm^3

Density=8.96 g/cm^3=\frac{Mass}{Volume}=\frac{Mass}{130,000 cm^3}

m=Density\times Volume=8.96 g/cm^3\times 130,000=1,264,800 g

m = 1,264,800 g = 1,264.800 kg (1 kg = 1000 g)

The mass of the sample is 1264.800 kg.

3 0
3 years ago
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