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stiv31 [10]
3 years ago
5

How many oxygen atoms are there in 6.00 g of sodium dichromate, na2cr2o7?

Chemistry
1 answer:
mel-nik [20]3 years ago
6 0
Answer is: there are 9,7·10²² atoms of oxygen.
m(Na₂Cr₂O₇) = 6,00 g.
n(Na₂Cr₂O₇) = m(Na₂Cr₂O₇) ÷ M(Na₂Cr₂O₇).
n(Na₂Cr₂O₇) = 6 g ÷ 262 g/mol.
n(Na₂Cr₂O₇) = 0,023 mol.
n(Na₂Cr₂O₇) : n(O) = 1 : 7.
n(O) = 7 · 0,023 mol.
n(O) = 0,161 mol.
N(O) = 0,161 mol · 6,022·10²³ 1/mol.
N(O) = 9,7·10²².
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Be sure to answer all parts.
sergey [27]

The  moles of O2 are needed to react completely with 1.00 mol of C₂H₂ is 5 mol , 0.23  moles of C₂H₂ are needed to form 0.46 mol of CO₂ .

<h3>What is a Balanced Reaction ?</h3>

A balanced reaction is a reaction in which the number of atoms present in the reactants is equal to the number of atoms in the products.

It is given in the question that

the combustion of Acetylene is given by

2 H―C≡C―H + 5 O₂ → 4 CO₂ + 2 H₂O

Given moles of Acetylene = 1 mol

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as the mole fraction of Acetylene to Oxygen is 1 :5

The mole of Acetylene needed to form 0.46 mol of CO₂ is ?

mole fraction of CO₂ to Acetylene is 4:2

Therefore 0.23 moles of CO₂ is required.

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Cacodyl, which has an intolerable garlicky odor and is used in the manufacture of cacodylic acid, a cotton herbicide, has a mass
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The molecular formula of cacodyl is C₄H₁₂As₂.

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<u>Let's assume we have 1 mol of cacodyl</u>, in that case we'd have 209.96 g of cacodyl and the<u> following masses of its components</u>:

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Those amounts of moles represent the amount of each component in 1 mol of cacodyl, thus, the molecular formula of cacodyl is C₄H₁₂As₂.

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