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3 years ago

How does solubility differ between small versus large carbohydrates? Explain.

Chemistry

1 answer:

EleoNora [17]3 years ago

5 0

Answer with Explanation:

Small and large carbohydrates have diverse structural properties. Such property allow them to have different solubility.

Solubility is a chemical property of a substance that allows it to dissolve in a given solvent.

Carbohydrates are made up of "monosaccharides." These are simple sugars and are considered small carbohydrates. On the contrary, "polysaccharide" is an example of a large carbohydrate. Monosaccharides are soluble in water while many polysaccharides are not soluble in water.

The high solubility of monosaccharides is mainly due to the presence of hydroxide (OH) groups. These groups are always ready to bond with water (H₂O). Many polysaccharides are not soluble in water because of intermolecular interactions that prevents it from binding with water. Its dissolution process is different when compared to the smaller molecules.

So, this explains the answer.

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How many moles of C8H18 contain 9.25 × 1024 molecules of C8H18 ?

fiasKO [112]

One mole of any material contains 6.02 * 10e23 atoms or molecules. This is the Avogadro number. So 9.25 * 10e24 atoms are contained in (9.25*10e24 / 6.02 * 10e23) = 15.36 moles. So the answer is that moles of C8H18 is 15.36 moles

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3 years ago

Choose two different particles found in the air. Explain how they are different and how they are the same

BARSIC [14]

Answer:

Dust and smoke.

Explanation:

Dust and smoke are two different particles present in the air. Dust and smoke are different from one another due to their origin. Smoke formed from burning of materials while dust refers to the soil particles lifted by the wind due to their light weight. Dust and smoke are similar to each other due to their small in size, infinite number means uncountable and light weight.

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3 years ago

How do I balance these equations

Svet_ta [14]

Easy you can't touch the subscripts so u need to add coiffents like a puzzle if you do this then it will chance this 1st name each element on each side then say how much it's worth then see what you need to chance like this
Ti=1
Cl=4
Mg=1.
On the other side

Ti=1
Mg=1
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3 years ago

The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

Answer: The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

For $_{77}^{191}\textrm{Ir}$ isotope:

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

For $_{77}^{193}\textrm{Ir}$ isotope:

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

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3 years ago

If i rub a balloon on a piece of paper then hold it against my head my hair will stand up why is that?

Alex_Xolod [135]

Static electricity is what occurs.

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3 years ago