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3 years ago

The charges of a set of isoelectronic ions vary from 3+ to 3-. Place the ions in order of increasing size.

Chemistry

1 answer:

ser-zykov [4K]3 years ago

4 0

Answer:

Explanation:

Iso-electronic species have same number of electrons . Positive charged ions will have smaller size . As electrons add , size increases due to electronic repulsion .

Following species are isoelectronic .

Al³⁺ < Mg²⁺ < Na¹⁺ < Ne < F⁻¹ < O⁻² < N⁻³

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How does the electron configuration of elements within the same group compare? (A.) They all have their valence electrons in the

lesya [120]

Answer:

B.They all have their valence electrons in the same type of subshell

Explanation:

The electron configurations of elements in the same group (column) of the periodic table have them in the same type of subshell.
But the subshells may be of different shells. Thus , the energies of them need not be the same.
For example , The Alkalai Metals are found in the first column of the periodic table Group IA. This set of elements all have valence electrons in only the ' $s$ ' orbital and because they are in the first column they all have $s^{1}$ configuration. i.e,

H $1s^1$
Li $1s^2 2s^1$
Na $1s^2 2s^2 2p^6 3s^1$
K $1s^2 2s^2 2p^6 3s^2 3p^64s^1$

5 0

3 years ago

A gas mixture contains 10.0 mole% H2O (v) and 90.0 mole % N2. The gas temperature and absolute pressure at the start of each of

Rainbow [258]

Answer: (a). T = 38.2 °C (b). V = 1.3392 cm³ (c). ii and iii

Explanation:

this is quite easy to solve, i will give a step by step analysis to solving this problem.

(a). from the question we have that;

the Mole fraction of Nitrogen, yи₂ = 0.1

Also the Mole fraction of Water, yн₂o = 0.1

We know that the vapor pressure is equal to the partial pressure because the vapor tends to condense at due point.

ρн₂o = ṗн₂o

= yн₂oP = 0.1 × 500 mmHg = 50 mmHg

from using Antoine equation, we apply the equation

logρн₂o = A - B/C+T

T = B/(A - logρн₂o) - C

= 1730.63 / (8.07131 - log 50mmHg) - 223.426

T = 38.2 °C

We have that the temperature for the first drop of liquid form is 38.2 °C

(b). We have to calculate the total moles of gas mixture in a 30 litre flask;

n = PV/RT

n = [500(mmHG) × 30L] / [62.36(mmHGL/mol K) × 323.15K] = 0.744 mol

Moles of H₂O(v) is 0.1(0.744) = 0.0744 mol

Moles of N₂ is 0.9(0.744) = 0.6696 mol

we have that the moles of water condensed is 0.0744 mol i.e the water vapor in the flask is condensed

Vн₂o = 0.0744 × 18 / 1 (g/cm³)

Vн₂o = 1.3392 cm³

Therefore, the volume of the liquid water is 1.3392 cm³

(3). (ii) and (iii)

The absolute pressure of the gas and The partial pressure of water in the gas would change if the barometric pressure drops.

cheers i hope this helps!!!!

4 0

3 years ago

Determine the amount of heat(in Joules) needed to boil 5.25 grams of ice. (Assume standard conditions - the ice exists at zero d

Yuki888 [10]

Following are important constant that used in present calculations
Heat of fusion of H2O = 334 J/g
Heat of vaporization of H2O = 2257 J/g 
Heat capacity of H2O = 4.18 J/gK

Now, energy required for melting of ICE = 334 X 5.25 = 1753.5 J .......(1)
Energy required for raising the temperature water from 0 oC to 100 oC = 4.18 X 5.25 X 100 = 2195.18 J .............. (2)
Lastly, energy required for boiling water = 2257X 5.25 = 11849.25 J ......(3)

Thus, total heat energy required for entire process = (1) + (2) + (3)
= 1753.5 + 2195.18 + 11849.25
= 15797.93 J
 = 15.8 kJ
Thus, 15797.93 J of energy is needed to boil 5.25 grams of ice.

7 0

3 years ago

5 points What is the name of the atom pictured here? Use a periodic table if needed. *

photoshop1234 [79]

Answer:

There is nothing attached to this question so I unfortunately cannot help you

Explanation:

3 0

3 years ago

Please help.This is due tomorrow.It's worth 2 grades.Please help.God bless u.Please and thankyou so much.

Daniel [21]

Answer:

1. False - compression

2. True

3. False - transform faults

4. False - horizontally

5. True

6. False- perpendicular

7. False - away from

8. False - increase

9. True

10. True

Explanation:

1. Mountains, oceanic trenches, and rift valleys are created by tension and compression stress. They are formed by divergent and convergent boundaries. Compression stress occurs when plates are pushing against each other, while tension stress occurs when the plates are pulling away from each other.

**Shear stress happens when the plates grind against each other. Often found in transform boundaries.

2. Transform faults happen when two plates glide or slide against each other. These areas are called transform boundaries. Transform faults occur in the ocean. When these boundaries are formed on land, they are called strike-slip faults.

3. Shear stress that occur in transform boundaries produce transform faults. These faults are usually identified by long faults and ridges. Sometimes small ponds form in the cracks due to deposition.

*** Rift valleys are produced by divergent boundaries or tension stress, when the plates are pulled apart.

4. Transform boundaries are formed when two plates slides against each other. Transform faults are formed in these boundaries and the movement of the plates are horizontal.

*** They do not move vertically.

5-6. Mid-oceanic ridges are segmented or divided by transform faults. The transform faults in the mid-oceanic ridges are perpendicular to the oceanic ridges. They separate them into distinct segments and can run across for hundreds of kilometers

7. New faults form as they move away from the ridges. Mid oceanic ridges are formed when the plates move apart, pushing the seafloor outwards and along with that, the transform faults. When new crust however overlaps the transform fault, they stop moving against each other, and start moving side by side, creating a crack.

8. Transform faults increase in size as long as the plates continue to move. The areas of transform faults, especially in the surface create earthquake faults.

9. Faults at the surface can be part of a larger underground system. Some faults can cut across continental crusts. These faults are created by different geological processes, like compression stress from convergent boundaries, tension stress from divergent boundaries, and shear stress from transform boundaries.

10. Fault zones are areas where you can find different faults formed, relatively close to each other. The faults in fault zones can be shallow or deeper like the fault zone Sierra Madre.

6 0

3 years ago