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3 years ago

How many miles of ammonia are need to produce 45.5 grams of water

Chemistry

1 answer:

shepuryov [24]3 years ago

3 0

Answer:

1.69 moles of ammonia are needed to produced 45.5 g of water.

Explanation:

Given data:

Mass of water = 45.5 g

Moles of ammonia required = ?

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45.5 g/ 18 g/mol

Number of moles = 2.53 mol

Now we will compare the moles of water with ammonia.

H₂O : NH₃

6 : 4

2.53 : 4/6×2.53 = 1.69 mol

1.69 moles of ammonia are needed to produced 45.5 g of water.

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Answer:

43.1atm is the pressure using gas law and 27.2atm using Van der Waals Law.

Explanation:

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PV = nRT

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500g * (1mol / 70.90g) = 7.052 moles

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$P + a(\frac{n}{V})^2 = \frac{nRT}{(V-nb)}$

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