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Alexandra [31]
3 years ago
5

An object of mass 0.5 kg is swung in uniform circular motion. The radius is 2 meters, and the force exerted is 4 N. Calculate th

e centripetal acceleration.
Chemistry
1 answer:
ZanzabumX [31]3 years ago
7 0

Answer:

8 m/s²

Explanation:

m = 0.5kg

r = 2m

F = 4 N

f=  \frac{ {mv}^{2} }{r}

make v the subject

v =  \sqrt{( \frac{fr}{m}) }

v = √(4×2)/0.5

v = √16

v = 4 m/s

a =   \frac{ {v}^{2} }{r}

a = 4²/2

a = 16/2

a = 8 m/s²

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When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation of two new nuc
user100 [1]

Answer:

^{139}_{56}Ba

Explanation:

The fission reaction taking place given in the question is:

^{235}_{92}U+^{1}_{0}n\rightarrow ^{A}_{Z}Ba+^{94}_{36}Kr+3^{1}_{0}n

The mass is conserved in the reaction.

So,

235 + 1 = A + 94 + 3×1

A = 139 g/mol

Also, number o protons remain same. So,

92  = Z + 36

Z = 56

The isotopic symbol is ^{139}_{56}Ba

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3 years ago
The constant
Zigmanuir [339]

Answer:

75 kJ/mol

Explanation:

The reactions occur at a rate, which means that the concentration of the reagents decays at a time. The rate law is a function of the concentrations and of the rate constant (k) which depends on the temperature of the reaction.

The activation energy (Ea) is the minimum energy that the reagents must have so the reaction will happen. The rate constant is related to the activation energy by the Arrhenius equation:

ln(k) = ln(A) -Ea/RT

Where A is a constant of the reaction, which doesn't depend on the temperature, R is the gas constant (8.314 J/mol.K), and T is the temperature. So, for two different temperatures, if we make the difference between the two equations:

ln(k1) - ln(k2) = ln(A) - Ea/RT1 - ln(A) + Ea/RT2

ln (k1/k2) = (Ea/R)*(1/T2 - 1/T1)

k1 = 8.3x10⁸, T1 = 142.0°C = 415 K

k2 = 6.9x10⁶, T2 = 67.0°C = 340 K

ln(8.3x10⁸/6.9x10⁶) = (Ea/8.314)*(1/340 - 1/415)

4.8 = 6.39x10⁻⁵Ea

Ea = 75078 J/mol

Ea = 75 kJ/mol

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Which question the top part, middle or the 7 covalents?

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