hmax = 5740.48 m. The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.
This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.
V₀ = 420m/s and θ₀ = 53.0°
So, when the cannonball is fired it has horizontal and vertical components:
V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s
V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s
When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:
Vy = V₀y - g tₐ = 0
tₐ = V₀y/g
tₐ = (335.43m/s)/(9.8m/s²) = 34.23s
Then, the maximum height is reached in the instant tₐ = 34.23s:
h = V₀y tₐ - 1/2g tₐ²
hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²
hmax = 11481.77m - 5741.29m
hmax = 5740.48m
Answer:
oil production in the USA are majorly from this states:
1.Texas
2. North Dakota
3. California
4. Alaska
5. New Mexico
6. Oklahoma
7.Colorado
8. Wyoming
Explanation:
While other states have seen a boom in recent years, Texas is still the epicenter of the U.S. oil industry, with 27 operable refineries, more than any state. Texas produced 1.2 billion barrels of oil in 2014, which accounted for 36% of total U.S. output, and the state has almost one-third of all proven oil reserves with 10.5 billion barrels.
The final speed of the car at the given conditions is 30.1 m/s.
The given parameters:
- <em>Mass of the car, m = 1700 kg</em>
- <em>Velocity of the car, v = 21 m/s</em>
- <em>Time of motion, t = 10 s</em>
- <em>Additional energy provided by the engine, E₁ = 22,000 J</em>
- <em>Energy used in overcoming friction, E₂ = 3,666.67 J</em>
The change in the energy applied to the car is calculated as;
The final speed of the car is calculated as follows;
Thus, the final speed of the car at the given conditions is 30.1 m/s.
Learn more about change in kinetic energy here: brainly.com/question/6480366
How heavy is the rock? comment and i will tell you answer
Answer:
b. The entropy of a pure, perfect crystalline substance at absolute zero is zero.
Explanation:
There are three laws of thermodynamics which are used to define the physical quantities and parameters like the energy, entropy, temperature. These parameters are used to characterize thermodynamic systems which are at thermal equilibrium.
The third law of thermodynamics:-
According to third law of thermodynamics, the entropy of the system at absolute zero temperature is a very well-defined constant. Also, for the entropy of the perfect crystalline solid which is at absolute zero is equal to zero exactly.
Thus, the correct option is:- b. The entropy of a pure, perfect crystalline substance at absolute zero is zero.
