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Umnica [9.8K]
3 years ago
14

A 2.0-kg block sliding on a frictionless, horizontal surface is attached to one end of a horizontal spring (k = 600 N/m) which h

as its other end fixed. The speed of the block when the spring is extended 20 cm is equal to 3.0 m/s. What is the maximum speed of this block as it oscillates?
Physics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

Maximum speed of the block, v_{max} = 4.58 m/s

Explanation:

Mass of the block, m = 2.0 kg

Spring constant, k = 600 N/m

Spring extension, x = 20 cm = 0.2 m

Speed of the block due to the extension, v = 3.0 m/s

First, Potential energy, PE stored in the spring:

PE = 0.5 kx²

PE = 0.5 * 600 * 0.2²

PE = 12 J

Calculate the kinetic energy of the block due to the extension:

KE_x = 0.5 mv^2\\KE_x = 0.5 * 2 * 3^2\\KE_x = 9 J

The maximum Kinetic Energy of the block will be:

KE_{max} = 0.5 m v_{max}^2\\KE_{max} = 0.5 * 2 * v_{max}^2\\KE_{max} =  v_{max}^2

KE_{max} = KE_x + PE\\v_{max}^2 = 9 + 12\\ v_{max}^2 = 21\\ v_{max} = \sqrt{21} \\ v_{max} = 4.58 m/s

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2 years ago
the maximum intensity levels of a trumpet, trombone, and a bass drum, each at a distance of 3m are 94 dB, 107dB, and 113dB respe
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Answer:

β = 114 db

Explanation:

The intensity of sound in decibles is

          β = 10 log \frac{I}{I_{o}}

in most cases Io is the hearing threshold 1 10-12 W / cm²

let's calculate the intensity of each instrument

            I / I₀ = 10 (β / 10)

            I = I₀ 10 (β / 10)

trumpet

            I1 = 1 10⁻¹² 10 (94/10)

            I1 = 2.51 10⁻³ / cm²

Thrombus

           I2 = 1 10⁻¹² 10 (107/10)

           I2 = 5.01 10-2 W / cm²

low

           I3 =1 1-12    (113/10) W/cm²

            I3 = 1,995 10-1 W / cm²

when we place the three instruments together their sounds reinforce

           I_total = I₁ + I₂ + I₃

           I_ttoal = 2.51 10-3 + 5.01 10-2 + ​​1.995 10-1

           I_total = 0.00251 + 0.0501 + 0.1995

           I_total = 0.25211 W / cm²

let's bring this amount to the SI system

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An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces
yKpoI14uk [10]

Answer:

i. 15.6 m/s

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Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

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Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

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initial velocity of the player, u = 9.4 m/s

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So that,

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                    = 1435.2

Impulse on the player is 1.44 KNs.

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