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vlada-n [284]
3 years ago
13

Abdou was explaining to a classmate that graphite is a good lubricant because it is bonded in layers that easily slip over each

other. Which image shows this quality? HELP ASAP!!!!
Physics
2 answers:
lesantik [10]3 years ago
3 0

Answer: The correct image is the one with 5 rows, and 9 hexagons in each row.

Explanation:

Just took the quiz

ivanzaharov [21]3 years ago
3 0

Answer:this is the right one.

Explanation:

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A battery is used to power a flashlight. When the flashlight is in use, what type of energy is lost during energy transformation
diamong [38]

Answer:

The answer is chemical energy

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The new deal helped fix the economy but was not the perfect solution​
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you will find your answer through this link

https://www.britannica.com/event/New-Deal

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3 years ago
The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in volt
Troyanec [42]

Answer:

I = 0.09[amp] or 90 [milliamps]

Explanation:

To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.

V = I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohm]

Now, we replace the values of the first current into the equation

V = 180*10^-3 * R

V = 0.18*R (1)

Then we have that the resistance is doubled so we have this new equation:

V = I*(2R) (2)

The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.

V = V

0.18*R = I*2*R

I = 0.09[amp] or 90 [milliamps]

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3 years ago
Blood ki kami se konsa rog hota hai?​
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An ideal refrigerator does 130. 0 j of work to remove 780. 0 j of heat from its cold compartment during each cycle. what is the
zheka24 [161]

The refrigerator's coefficient of performance is 6.

The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.

As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.

The heat produced in the cold compartment, H = 780.0 J

Work done in ideal refrigerator, W = 130.0 J

Refrigerator's coefficient of performance = H/W

                                                                     = 780/130

                                                                     = 6

Therefore, the refrigerator's coefficient of performance is 6.

Energy conservation requires the exhaust heat to be = 780 + 130

                                                                                          = 910 J

Learn more about  coefficient here:

brainly.com/question/18915846

#SPJ4

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