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vlada-n [284]
3 years ago
13

Abdou was explaining to a classmate that graphite is a good lubricant because it is bonded in layers that easily slip over each

other. Which image shows this quality? HELP ASAP!!!!
Physics
2 answers:
lesantik [10]3 years ago
3 0

Answer: The correct image is the one with 5 rows, and 9 hexagons in each row.

Explanation:

Just took the quiz

ivanzaharov [21]3 years ago
3 0

Answer:this is the right one.

Explanation:

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What is the mass of the sun plus all the planets in solar system?
Savatey [412]
It’s a very huge mass
3 0
2 years ago
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Which statement is true about the thermal energy of an object? Choose the correct answer. 1). Thermal energy is the internal pot
Brums [2.3K]
This thermal energy flows as heat within the box and floor, ultimately raising the temperature of both of these objects.
5 0
3 years ago
"Light traveling in a medium with a refractive index 1.11 is incident on a plate of another medium with index of refraction 1.66
Kamila [148]

Answer:

56°

Explanation:

Brewsters angle can be simply derived from

n1sin theta1= n2sintheta2= n2costheta1

because the reflected light will be 100% polarized if it is reflected at an angle 90o to the refracted light. Hence, Brewsters angle is

Tan theta= n2/n1

1.66/1.11= 1.495

Theta = 56°

Explanation:

7 0
4 years ago
Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set in
Yuki888 [10]

Answer:

  0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

  T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

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For d = 0.20 meters, the period is ...

  T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

_____

<em>Additional comment</em>

The formula for the oscillator period is usually seen as ...

  T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

  k = mg/d

Using that in the formula, we find it simplifies to ...

  T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}

5 0
2 years ago
distant galaxy emits light that has a wavelength of 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm.
a_sh-v [17]

Answer:

The speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

Explanation:

We have,

(a) Wavelength emitted by light at distant galaxy is 434.1 nm. On earth, the wavelength of this light is measured to be 438.6 nm. It can be seen that the wavelength of light reduces as it reaches Earth. It is called Red shift. As per Doppler's effect, we can say that the galaxy is receding from the Earth.

(b) Let v is the speed of the galaxy relative to the Earth. It can be given by :

v=c(\dfrac{\lambda'}{\lambda}-1)\\\\v=3\times 10^8\times (\dfrac{438.6 }{434.1 }-1)\\\\v=3\times 10^8\times (\dfrac{438.6}{434.1}-1)\\\\v=0.0103\cdot3\cdot10^{8}\\\\v=3.09\times 10^6\ m/s

So, the speed of the galaxy relative to the Earth is 3.09\times 10^6\ m/s.

4 0
3 years ago
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