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nasty-shy [4]
3 years ago
14

For a closed system, the change in entropy for a reversible process is _________ the change in entropy for an irreversible proce

ss between the same two states
a. greater than
b. less than
c. the same as
Chemistry
1 answer:
Grace [21]3 years ago
5 0

Answer:

c. the same as

Explanation:

for a closed system:

⇒ ΔS > 0.....irreversible process

⇒ ΔSrev = ∫ dQ/T

for an irreversible process, ΔS is not the same as in a reversible process, since more than one reversible process is needed for the two ΔS to be equal.

⇒ ΔSirrev = ΔSrev1 + ΔSrev2 + ....

but if the initial and final states are the same, ΔS for an irreversible process can be calculated as if it were a reversible process.

⇒ ΔSirrev = ΔSrev

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Suppose 11.4g of ammonium chloride is dissolved in 250 ml of a 0.3M aqueous solution of potassium carbonate. Calculate the final
Sindrei [870]

Answer:

The molarity of the final ammonium cation is 0.252M

Explanation:

<u>Step 1:</u> Data given

Mass of ammonium chloride (NH4Cl) = 11.4 grams

Volume of 0.3 M aqueous solution of potassium carbonate (K2CO3) = 250 mL = 0.250L

<u>Step 2:</u> The balanced equation

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<u>Step 3:</u> Calculate moles of (NH4)Cl

moles (NH4)Cl = 11.4 grams /53.49 g/mol

Moles (NH4)Cl = 0.213 moles

<u>Step 4: </u>Calculate moles of K2CO3

Moles K2CO3 = Molarity * Volume

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<u>Step 5:</u> Calculate moles (NH4)Cl at the equilibrium

For 2 moles (NH4)Cl consumed, we need 1 mole of K2CO3 to produce 2 KCl and 1 mole of (NH4)2CO3

(NH4)2CO3l will dissolve in 2NH4+ + CO32-

Moles (NH4)2Cl = 0.213 moles - 2*0.075 = 0.063 moles

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<u>Step 6:</u> Calculate Molarity of NH4+

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The molarity of the final ammonium cation is 0.252M

5 0
3 years ago
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Answer:

A

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a is the right answer abi

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