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3 years ago

What is the effect of raising the temperature of a system at equilibrium?

1 answer:

3 0

This shifts chemical equilibria toward the products or reactants, which can be determined by studying the reaction and deciding whether it is endothermic or exothermic....

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A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh

andrew-mc [135]

Answer:

0.5

Explanation:

The energy of a charged capacitor is given by $\frac{1}{2}QC$ where $Q$ is the charge on it and $C$ is its capacitance. The capacitance is defined, geometrically, as

$\dfrac{\epsilon A}{d}$

where $\epsilon$ is a constant that is determined by the material between the plates, $A$ is the area of the plates and $d$ is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, $C_1$ at initial separation, $d_1$

$C_1=\dfrac{\epsilon A}{d_1}$

If separation is doubled, separation becomes $d_2=2d_1$ . Then the capacitance becomes

$C_2=\dfrac{\epsilon A}{d_2}$

$C_2=\dfrac{\epsilon A}{2d_1}$

$C_2=0.5\dfrac{\epsilon A}{d_1}$

$C_2=0.5C_1$

Initial energy, $E_1=\frac{1}{2}QC_1$

Final energy, $E_2=\frac{1}{2}QC_2= \frac{1}{2}Q\times0.5C_1$

$E_2=0.5\times\frac{1}{2}QC_1=0.5E_1$

Hence, $\frac{E_2}{E_1}=0.5$

5 0

3 years ago

A baseball of mass 1.23 kg is thrown at a speed of 65.8 mi/h. What is its kinetic energy?

frosja888 [35]

Given:

The mass of the ball is

$m=1.23\text{ kg}$

The speed of the ball is

$\begin{gathered} v=65.8\text{ mi/h} \\ \end{gathered}$

Required: calculate the kinetic energy of the baseball

Explanation: to calculate the kinetic energy of a body we will use the formula as

$K.E=\frac{1}{2}mv^2$

first, we convert velocity from mi/h into m/s.

we know that

$1\text{ mi=1609.34 m}$

and

$1\text{ h=3600 sec}$

then the velocity is

$\begin{gathered} v=\frac{65.8\times1602.34\text{ m}}{3600\text{ s}} \\ v=29.29\text{ m/s} \end{gathered}$

now plugging all the values in the above formula, we get

$\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times1.23\text{ kg}\times(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}$

Thus, the kinetic energy of the baseball is

$527.61\text{ J}$

4 0

2 years ago

An engine extracts 452.8kJ of heat from the burning of fuel each cycle, but rejects 266.7 kJ of heat (exhaust, friction,etc) dur

Svetlanka [38]

Answer: The thermal efficiency of the engine is 41.09 %.

Explanation:

Efficiency is the ratio of the useful work performed to the total energy expended or heat taken in.

Formula for thermal efficiency of engine is

$\eta=1- \frac{Q_2}{Q_1}\times 100$

$\eta$ = efficiency

${Q_2}$ = heat rejected = 266.7 kJ

${Q_1}$ = heat extracted = 452.8 kJ

Putting in the values we get:

$\eta=1- \frac{266.7 kJ}{452.8 kJ }\times 100$

$\eta=0.41\times 100$

$\eta =41.09\%$

The thermal efficiency of the engine is 41.09 %.

7 0

4 years ago

PLEASE ANSWER AS QUICK AS POSSIBLE!!!!!

horsena [70]

During the operation of fan we know that it is working on the electricity

So here when we connect the fan with electricity it uses the electrical energy and convert that energy into mechanical energy of fan

Fan uses this electrical energy to rotate the blades of fan and then it gives the high speed air to us

So here correct answer must be

motion energy

8 0

4 years ago

Consider two sizes of disk, both of mass M. One size of disk has radius R; the other has radius 4R. System A consists of two of

Harman [31]

Answer:

4 smaller disks

Explanation:

We are given;

Mass of smaller and larger disks = M

Radius of smaller disk = R

Radius of larger disk = 4R

Formula for moment of inertia about cylinder axis is:

I = ½MR²

Thus;

For small disk, I_small = ½MR²

For large disk, I_large = ½M(2R)² = 2MR²

We are told that moment of inertia of System A consists of two of the larger disks. Thus;

I_A = 2 × I_large = 2 × 2MR²

I_A = 4MR²

We are also told that System B consists of one of the larger disks and a number of the smaller disks. Thus;

I_B = I_large + n(I_small)

Where n is the number of smaller disks.

I_B = 2MR² + n(½MR²)

I_B = MR²(2 + n/2)

We are told that the moment of inertia for system A equals the moment of inertia for system B. Thus;

I_A = I_B

So;

4MR² = MR²(2 + n/2)

MR² will cancel out to give;

4 = 2 + n/2

Multiply through by 2 to give;

8 = 4 + n

n = 8 - 4

n = 4

5 0

3 years ago